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3 years ago

I need help with this math.

Mathematics

1 answer:

Shkiper50 [21]3 years ago

6 0

Answer:

B, D, E

Step-by-step explanation:

The parenthesis can be removed and this is the same answer as D.

Moving the parenthesis to the first two terms gives B.

Lastly using multiplication sign rules that say -(-) = +, E is the same expression.

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Lila decided to make more baked goods for the bake sale. She used 1/8 lb less flour to make bread than to make cookies. She used

satela [25.4K]

Answer:

Ok so we are trying to find out how much flour she used to make brownies so we already know that she used 1/2 flour to make bread and She uses 1/8 flour less flour to make bread than to make cookies so if we add 1/2 and 1/8 we will get the amount of flour she used to make the cookies so 1/2 + 1/8 = 5/8 so now that we have the amount of flour she used to make the cookies we know that that is 1/4 more flour than brownies so if we subtract 5/8 by 1/4 we will get are answer to how much flour she uses to make brownies so 5/8 - 1/4 = 3/8 and that's your answer do you understand?

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The sum of three numbers is 8. The third is 9

Ierofanga [76]

Answer:

→ First value is 1

→ Second value is 2

→ Third value is 5

Step-by-step explanation:

• let numbers be x, y and z

${ \tt{z = 8y - 9 - - - (eqn \: 1)}} \\ \\ { \tt{10x = 8y - 7 - - - (eqn \: 2)}} \\ \\ { \tt{x + y + z = 8 - - - (eqn \: 3)}}$

• from eqn 2, make x the subject:

${ \tt{x = \frac{8y - 7}{10} }} \\$

• substitute all variables in eqn 3:

${ \tt{ \frac{8y - 7}{10} + y + 8y - 9 = 8}} \\ \\ { \tt{8y - 7 + 10y + 80y - 90 = 80}} \\ \\ { \tt{98y = 177}} \\ \\ { \boxed{ \tt{ \: y = 1.8}}}$

• find z

${ \tt{z = 8y - 9}} \\ \\ { \tt{z = 8(1.8) - 9}} \\ \\ { \tt{z = 14.4 - 9}} \\ \\ { \boxed{ \tt{ \: z = 5.4 \: }}}$

• find x:

${ \tt{x = \frac{8(1.8) - 7}{10} }} \\ \\ { \tt{x = \frac{7.4}{10} }} \\ \\ { \boxed{ \tt{ \: x = 0.74 \: }}}$

Rounding to nearest value:

${ \boxed{ \rm{x = 1}}} \\ { \boxed{ \rm{y =2 }}} \\ { \boxed{ \rm{z = 5}}}$

7 0

3 years ago

Compare the process of solving |x – 1| + 1 < 15 to that of solving |x – 1| + 1 > 15.

kicyunya [14]

In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.

In the second case we'd also subtract 1 from both sides, and would obtain
|x-1|>14.

What would the graphs look like?

In the first case, the graph would be on the x-axis with "center" at x=1. From this center count 14 units to the right, and then place a circle around that location (which would be at x=15). Next, count 14 units to the left of this center, and place a circle around that location (which would be -13). Draw a line segment connecting the two circles. Notice that all of the solutions are between -13 and +15, not including these endpoints.

In the second case, x has to be greater than 15 or less than -13. Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right. None of the values in between are solutions.

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3 years ago

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Here is a polygon:

Tju [1.3M]

Answer:

the dialation is in d and a , and d and a have viagra

Step-by-step explanation:

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3 years ago

What is greater -3 or 3

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