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2 years ago

What is the greatest common factor of 8x and 22xy?

Mathematics

1 answer:

RideAnS [48]2 years ago

7 0

The greatest common factor of 8x and 22yx is 2x.

I got this answer by factoring out 8 and 22:

8: 1,2,4,8

22: 1,2,11,22

Their greatest common factor was 2 and they both have x.

Your answer is 2x.

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What is the component form of the vector represented by 2a when a⃗ =〈−2,3〉?

Paladinen [302]

Answer:

$\vec v = 2\cdot \vec a = \langle -4,6 \rangle$

Step-by-step explanation:

Let $\vec a = \langle -2, 3 \rangle$ , we need to determine $\vec v = 2\cdot \vec a$ , which can be found by applying the following property:

$\alpha \cdot \langle x,y \rangle = \langle \alpha \cdot x, \alpha \cdot y\rangle$ , $\forall \,\alpha,x,y\in \mathbb{R}$ (1)

Then,

$\vec v = 2\cdot \langle -2,3 \rangle$

$\vec v = \langle -4,6 \rangle$

8 0

2 years ago

Please help

ehidna [41]

Answer:

The length between the two points is RT = 1.3 units

Step-by-step explanation:

The coordinates of the point R and T are R(2,1.2) and T(2,2.5).

Now, by DISTANCE FORMULA:

The distance between two coordinates P and Q with coordinate P(a,b) and Q(c,d) is given as:

$PQ = \sqrt{(a-c)^2 + (b-d)^2}$

So, here the distance RT = $\sqrt{(2-2)^2 + (2.5 - 1.2)^2} = \sqrt{0^2 + (1.3)^2} = 1.3$

or, RT = 1.3 units

Hence, the length between the two points is RT = 1.3 units

6 0

2 years ago

Anna and Veronica are on the opposite sides of a tower of 160 meters height. They measure the angle of elevation of the top of t

MAXImum [283]

Answer: The distance between the girls is 362.8 meters.

Step-by-step explanation:

So we have two triangle rectangles that have a cathetus in common, with a length of 160 meters.

The adjacent angle to this cathetus is 40° for Anna, then the opposite cathetus (the distance between Anna and the tower) can be obtained with the relationship:

Tan(A) = opposite cath/adjacent cath.

Tan(40°) = X/160m

Tan(40°)*160m = 134.3 m

Now, we can do the same thing for Veronica, but in this case the angle adjacent to the tower is 55°

So we have:

Tan(55°) = X/160m

Tan(55°)*160m = X = 228.5 m

And we know that the girls are in opposite sides of the tower, so the distance between the girls is equal to the sum of the distance between each girl and the tower, then the distance between the girls is:

Dist = 228.5m + 134.3m = 362.8m

8 0

2 years ago

What is the value of x

GarryVolchara [31]

<h2><u>We can solve it using trigonometric values.</u></h2>

<h3>So , <u> </u><u>sin</u><u> </u><u>θ</u><u> </u> = ( Perpendicular / Hypotenuese )</h3>

<h2><u>Given</u><u> </u></h2>

Perpendicular = x

Hypotenuese = 30

${ \sf{sin \: \: 45 {}^{ \degree} = \dfrac{1}{ \sqrt{2} } = \dfrac{x}{ 30} }}$