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Andrew [12]
3 years ago
7

True or False: Tangent line approximation works at any point on any graph.

Mathematics
1 answer:
Tresset [83]3 years ago
5 0
That is false. Tangent line has to start from a specific line( either the (x-axis) or the (y-axis). 

Hope this helped. :)

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x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
How many solutions does a system of equations have when solving results in the statement 3 = 5?
blagie [28]
There would be no solutions
8 0
3 years ago
Find the missing side. Round the answers to TWO decimal places.
likoan [24]

Answer:

ok so we need to use the pythagorean theorem

a^2+b^2=c^2

3^2+10^2=

the square root of 109

10.4403065089

10.44

Hope This Helps!!!

3 0
2 years ago
B. Pablo's goal is to have $5,000 after 4 years. Is this possible if he
Keith_Richards [23]

Complete question is;

If Pablo invests $4200 for 3 years and earns $630

A) what is the simple interest rate?

B) Pablo’s goal is to have $5000 after 4 years. Is it possible with a rate of 6%? Explain.

Answer:

A) Rate = 5%

B) Yes, it is possible for him to earn $5000 after 4 years with an interest rate of 6%

Step-by-step explanation:

A) Formula for interest is;

i = PRT

We are given;

i = 630

P = 4200

T = 3

Making R the subject;

R = i/PT

R = 630/(4200 × 3)

R = 0.05

This is 5%

B) Formula for value of principal after interest period is;

A = P(1 + RT)

P = 4200

R = 6% = 0.06

T = 4 years

Thus;

A = 4200(1 + (0.06 × 4))

A = $5208

Thus, it is possible for him to earn $5000 after 4 years with an interest rate of 6%

3 0
2 years ago
Pls help with both ............
Ilia_Sergeevich [38]
The first one is 1,600
the second one is 321,489
3 0
2 years ago
Read 2 more answers
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