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Andrew [12]
4 years ago
7

True or False: Tangent line approximation works at any point on any graph.

Mathematics
1 answer:
Tresset [83]4 years ago
5 0
That is false. Tangent line has to start from a specific line( either the (x-axis) or the (y-axis). 

Hope this helped. :)

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Let the sample space be S = 1, 2 ,3 , 4, 5, 6 suppose those outcomes are equally likely. Compute the probability of the event E
Mekhanik [1.2K]

Given:

Sample space be S = 1, 2 ,3 , 4, 5, 6.

The outcomes are equally likely.

To find:

The probability of the event E ="an even number".

Solution:

We have,

Sample space is S = 1, 2 ,3 , 4, 5, 6.

So, the total number of outcomes is 6.

E ="an even number".

E = {2,4,6}

So, the total number of favorable outcomes is 3.

The probability of the event E is

P(E)=\dfrac{Favorable outcomes}{Total outcomes}

P(E)=\dfrac{3}{6}

P(E)=\dfrac{1}{2}

P(E)=0.5

Therefore, the probability of the event E is 0.5.

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A map uses a scale where 3 inches represents 4 miles. if the distance between two cities is shown on a map as 24 inches, how man
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Long Division: (3x^4-8x^3-x^2+9x+5) / (x-2) pleaseee answer this
Drupady [299]

3<em>x</em>⁴ = 3<em>x</em>³ • <em>x</em>, and

3<em>x</em>³ (<em>x</em> - 2) = 3<em>x</em>⁴ - 6<em>x</em>³

Subtract this from the numerator to get a remainder of

(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (3<em>x</em>⁴ - 6<em>x</em>³) = -2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5

-2<em>x</em>³ = -2<em>x</em>² • <em>x</em>, and

-2<em>x</em>² (<em>x</em> - 2) = -2<em>x</em>³ + 4<em>x</em>²

Subtract this from the previous remainder to get a new remainder of

(-2<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) - (-2<em>x</em>³ + 4<em>x</em>²) = -5<em>x</em>² + 9<em>x</em> + 5

-5<em>x</em>² = -5<em>x</em> • <em>x</em>, and

-5<em>x</em> (<em>x</em> - 2) = -5<em>x</em>² + 10<em>x</em>

Subtract this from the last remainder to get a new one of

(-5<em>x</em>² + 9<em>x</em> + 5) - (-5<em>x</em>² + 10<em>x</em>) = -<em>x</em> + 5

-<em>x</em> = -1 • <em>x</em>, and

-1 (<em>x</em> - 2) = -<em>x</em> + 2

This gives a new remainder of

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So, we have

(3<em>x</em>⁴ - 8<em>x</em>³ - <em>x</em>² + 9<em>x</em> + 5) / (<em>x</em> - 2) = 3<em>x</em>³ - 2<em>x</em>² - 5<em>x</em> - 1 + 3/(<em>x</em> - 2)

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4 years ago
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