A total of 192 units is planned, and the number of family units (2 and 3 bedroom townhouses) will equal to the number of 1 bedro
om units. If the number of 1 bedroom units will be 3 times the number of 3 bedroom units, find how many units of each type will be in the complex.
1 answer:
Answer:
96 one bedroom homes
64 two bedroom homes
32 three bedroom homes
Step-by-step explanation:
If x is the number of 1 bedroom homes, y is the number of 2 bedroom homes, and z is the number of 3 bedroom homes:
x + y + z = 192
x = y + z
x = 3z
Solve the system of equations using substitution or elimination. Using substitution:
x + x = 192
2x = 192
x = 96
z = x / 3
z = 32
y = x − z
y = 64
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Wow I got the first step
are you looking for the
intersection of the line perpendicular
to plane 1 thorough the origin and plane 2
for the first part???
That would simply be
38.14 ÷ 4 = 9.535
thus he scored 9.535 on each event
(-x-14)^2 = x^2 +14x+14x+196
which turns into x^2+28x+196.
hope this helps
and give thanks
Step-by-step explanation:
I have used substitution method here to find the value of x and y.
