The second cylinder is taller correct?
8 in < 11 in

If the height is also larger, the base is most likely larger too.

Wouldn't the largest cylinder have a Larger surface area?

8 0

4 years ago

Help me out with this

elena55 [62]

Let's follow the transformations that happen to A, to get to A' and A''.

Point A is at (-5, -2)

It moves to (-5, 2) which is where A' is located. Note the x coordinate stays the same while the y coordinate flips from negative to positive. This must mean we applied a reflection over the x axis.

That rule in general is $(x, y) \rightarrow (x,-y)$

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Now compare A'(-5,2) and A''(1,4). We can shift A' 6 units to the right and then 2 units up so we move from A' to A''.

Algebraically this is stated as $(x,y) \rightarrow (x+6, y+2)$

Whatever the x coordinate is, add 6 to it. For the y coordinate, we add on 2.

Applying that rule to B'(-1,2) gets us to

$(-1,2) \rightarrow (-1\textbf{+6}, 2\textbf{+2}) = (5,4)$

which is the proper location of B''

The same applies to moving C' to C''

$C' = (-5, 0) \rightarrow (-5\textbf{+6}, 0\textbf{+2}) = (1, 2) = C''$

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In summary, we started off by reflecting over the x axis. Then we applied the translation rule of "shift to the right 6 units, shift up 2 units".

In terms of algebra, combining the rules $(x,y) \rightarrow (x,-y)$ and $(x,y) \rightarrow (x+6, y+2)$ will have us end up with $(x,y) \rightarrow (x+6, -y+2)$