$\begin{array}{ccll} \$&km\\ \cline{1-2} 32&14\frac{2}{9}\\[1em] x&1 \end{array}\implies \cfrac{32}{x}=\cfrac{14\frac{2}{9}}{1}\implies \cfrac{32}{x}=14\frac{2}{9}\implies \cfrac{32}{x}=\cfrac{14\cdot 9+2}{9} \\\\\\ \cfrac{32}{x}=\cfrac{128}{9}\implies 288=128x\implies \cfrac{288}{128}=x\implies \stackrel{~\hfill \textit{2 bucks and 25 cents}}{\cfrac{9}{4}=x\implies 2\frac{1}{4}}=x$

4 0

2 years ago

Eric has $25 to purchase magazines and to pay for his lunch. Each

faust18 [17]

Answer:

Step-by-step explanation:

The maximum amount Eric can spend on magazines is $25 less the cost of lunch, $15.

The appropriate inequality sign would be less than since he cannot spend more than $25.

Also, the amount he can spend on magazines would be what is left after paying for lunch.

So the correct inequality is 4m - 15 < 25

8 0

2 years ago

2. Wpisz taką liczbę, aby rozwiązaniem równania była liczba 2.

lys-0071 [83]

I didn’t understand but when I understand I will help you

5 0

2 years ago