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3 years ago

Joshua and his four friends each have 1/2 package of crackers. HOW many packages of crackers do they have in all

Mathematics

2 answers:

denpristay [2]3 years ago

7 0

Answer:

2.5 packages of crackers

Step-by-step explanation:

multiply .5 by 5

good luck

please mark me brainliest

riadik2000 [5.3K]3 years ago

4 0

Answer:

2 1/2 packages of crackers

Step-by-step explanation:

You might be interested in

Please please help if you can it would mean a lot. Thank you!!

zheka24 [161]

11. 6:18 = 1:3
12. 12:48 = 1:4
13. 17:34 = 1:2
14. 8:64 = 1:8

15. 44:4 = 11:1
16. 121:11 = 11:1
17. 12:2 = 6:1
18. 4:2 = 2:1

19. 3:4 and 2:3 = 9:12 and 8:12
20. 1:6 and 3:14 = 7:42 and 9:42
21. 2:7 and 3:5 = 10:35 and 21:35
22. 5:2 and 3:1 = 5:2 and 6:2

Comparing Ratios:

1. 1.7 m = 170 cm
20:170 = 2:17

2. 160:8 = 20:1

3. 15:50 = 3:10

4. For every cup of milk she needs 5 cups of flour, so if she uses 3 cups of milk she'd need 15 cups of flour

Hopefully that helps :)

3 0

3 years ago

11 = − 3k − 22 − 8k K equals what?

butalik [34]

11 = -3k - 22 - 8k

11 = -11k - 22 added like terms (-3k and -8k)

+22 +22

33 = -11k

$\frac{33}{-11} = \frac{-11k}{-11}$

-3 = k

Answer: k = -3

3 0

3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

What is 75 over 100 in simplest form

kotykmax [81]

75/100 = 3/4
1. Divide by 25.(Both go into 25)
75 divided by 25 = 3
100 divided by 25= 4

3 0

3 years ago

Read 2 more answers

The temperature T of a refrigerator is at least 35°F and at most 41°F. Write a compound

s344n2d4d5 [400]

The compound inequality for the temperature T of a refrigerator that is at least 35°F and at most 41°F is 35 ≤ T ≤ 41

A compound inequality has two inequality statements joined together

The the temperature of the inequality is represented by T

The temperature T of a refrigerator is at least 35°F and at most 41°F

This means that the temperature falls between 35°F and 41°F

Since the temperature, T, is at most 41°F

This can be mathematically interpreted as

T ≤ 41

The temperature, T, is at least 35°F

35 ≤ T

Combining the two inequality statements 35 ≤ T and T ≤ 41, the compound statement formed is:

35 ≤ T ≤ 41

The compound inequality for the temperature T of a refrigerator that is at least 35°F and at most 41°F is 35 ≤ T ≤ 41

Learn more here: brainly.com/question/11316045

8 0

3 years ago