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3 years ago

11 = − 3k − 22 − 8k K equals what?

Mathematics

1 answer:

butalik [34]3 years ago

3 0

11 = -3k - 22 - 8k

11 = -11k - 22 added like terms (-3k and -8k)

+22 +22

33 = -11k

$\frac{33}{-11} = \frac{-11k}{-11}$

-3 = k

Answer: k = -3

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What are the X and Y intercepts of y= -2(x-4)2 +3

kari74 [83]

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And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

$y = -2(x-4)^2+3$

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, $-2(x-4)^2 + 3 = 0$

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$-2x^2-32-16x + 3 = 0$

$-2x^2-16x -29 = 0$

By solving this equation,

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3 years ago

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sleet_krkn [62]

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Step-by-step explanation:

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3 years ago

Jose car rental company charges $2.75 for a pick up plus $1.25 for each mile driven. How much would you pay to travel 25 miles ?

mote1985 [20]

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Step-by-step explanation:

The computation of the amount for traveling 25 miles is shown below:

Since it is given that the rental company charges $2.75 plus $1.25 for each mile

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3 years ago

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3 years ago

A random sample of n 1 = 249 people who live in a city were selected and 87 identified as a democrat. a random sample of n 2 = 1

kvasek [131]

Answer:

$CI=\{-0.2941,-0.0337\}$

Step-by-step explanation:

Assuming conditions are met, the formula for a confidence interval (CI) for the difference between two population proportions is $\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}$ where $\hat{p}_1$ and $n_1$ are the sample proportion and sample size of the first sample, and $\hat{p}_2$ and $n_2$ are the sample proportion and sample size of the second sample.

We see that $\hat{p}_1=\frac{87}{249}\approx0.3494$ and $\hat{p}_2=\frac{58}{113}\approx0.5133$ . We also know that a 98% confidence level corresponds to a critical value of $z^*=2.33$ , so we can plug these values into the formula to get our desired confidence interval:

$\displaystyle CI=(\hat{p}_1-\hat{p}_2)\pm z^*\sqrt{\frac{\hat{p}_1(1-\hat{p}_1)}{n_1}+\frac{\hat{p}_2(1-\hat{p}_2)}{n_2}}\\\\CI=\biggr(\frac{87}{249}-\frac{58}{113}\biggr)\pm 2.33\sqrt{\frac{\frac{87}{249}(1-\frac{87}{249})}{249}+\frac{\frac{58}{113}(1-\frac{58}{113})}{113}}\\\\CI=\{-0.2941,-0.0337\}$

Hence, we are 98% confident that the true difference in the proportion of people that live in a city who identify as a democrat and the proportion of people that live in a rural area who identify as a democrat is contained within the interval {-0.2941,-0.0337}

The 98% confidence interval also suggests that it may be more likely that identified democrats in a rural area have a greater proportion than identified democrats in a city since the differences in the interval are less than 0.

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2 years ago