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Serhud [2]
3 years ago
5

8. 71/5 -6 26 = ? A. 13 3/5 B.1 4/5 C.1 1/5 D.4/5

Mathematics
1 answer:
Damm [24]3 years ago
3 0

Answer:

I think it is A

Step-by-step explanation:

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Find x show ur work !!
Elis [28]

Answer:

x = 10

Step-by-step explanation:

A triangle's angles add up to 180 degrees, so 180-90 (the right angle) is 90 degrees. That means that

4x+6+3x+14 = 90. Then we simplify so

7x + 20 = 90. Then we can subtract 20 from each side so

7x = 70. Then, we find that

x = 10.

4 0
3 years ago
Read 2 more answers
I’ll mark you brainlist please help
Nina [5.8K]

Answer:

The x is the domain and the y is the range. It's still a function

Step-by-step explanation:

3 0
3 years ago
a ball is shot straight upward. with it's height, in feet, after t seconds given by the function f(t)=-16t^2+192t. Find the aver
jekas [21]

ANSWER

80  {ms}^{ - 1}

EXPLANATION

The average velocity of the ball is the rateof displacement over the total time.

The height of the ball, in feet, after t seconds is given by the function:

f(t)=-16t^2+192t

At time t=1, the height of the ball is

f(1)=-16(1)^2+192(1)

f(1)=-16+192 = 176ft

At time t=6, the height of the ball is

f(6)=-16(6)^2+192(6)

f(6)=-16(36)+192(6)

f(6)=-576+1152 = 576

The average velocity

=  \frac{f(6) - f(1)}{6 - 1}

=  \frac{576- 176}{6 - 1}

=  \frac{400}{5}

= 80  {ms}^{ - 1}

7 0
3 years ago
(Will give brainiest)<br><br>5y - x = 10<br><br>4x - 4y = 1<br><br>12 = 6x + 3y
kow [346]
Is there any answer choices to what we are looking for?
7 0
3 years ago
The graph is of a polynomial function f(x) of degree 5 whose leading coefficient is 1. The graph is not drawn to scale. Use the
LUCKY_DIMON [66]

roots of a polynomial are (x-c1)(x-c2)(x-c3) .......(x-cn). Basically, plug every root you have into a (x-__) and then multiply them all together. Just be careful of signs. If your root is positive, it is written as (x-__). If your root is negative, it is written (x+__)

<span>I got x^5-5x^4+5x^3+5x^2-6x</span>

<span>
</span>

<span>Hope this helps</span>

7 0
3 years ago
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