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3 years ago

What is the area of this trapezoid?

Mathematics

2 answers:

Vitek1552 [10]3 years ago

8 0

Answer:

400cm^2

Step-by-step explanation

equation: a+b/2 x h

19+25/2 x 20

44/2 x 20

22 x 20

440 (don't forget unit) and to square because we are finding the area

jenyasd209 [6]3 years ago

7 0

The formula of an area of a trapezoid:

$A=\dfrac{base_1+base_2}{2}\cdot height$

We have

$base_1=25\ cm\\\\base_2=19\ cm\\\\height=20\ cm$

Substitute:

$A=\dfrac{25+19}{2}\cdot20=\dfrac{44}{2}\cdot20=22\cdot20=440\ cm^2$

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[|] Answer [|]

$\boxed{X \ = \ 6}$

[|] Explanation [|]

3x + 5 = 23

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Read 2 more answers

The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1

AnnZ [28]

Answer:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

$\hat p=\frac{155}{200}=0.775$ estimated proportion of cell phone owners used text messaging

$p_o=0.73$ is the value to verify

$\alpha=0.1$ represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis: $p=0.73$

Alternative hypothesis: $p \neq 0.73$

The statistic to check this hypothesis is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

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