6 = -2b (cancel -2b on both sides)
6/-2 = b (divide both sides by -2)
-3 = b (simplify 6/2 to 3)
now switch sides
Answer: b = -3
Answer:
d. (3, 8)
Step-by-step explanation:
the coordinates of point W " on the final image is (3 8) Solution-means first the point is translated left by 4 units and translated up by 2 units then it is reflected across y axis. (the rules follow right to left approach) The co-ordinate of point W is ( 1 6 ). After 4 units translation to left and 2 units translation to up the co-ordinates
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
The first quartile of the data set is 28 because it is the median of the lower set.
I think every angle below 90 degrees
