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yan [13]
3 years ago
6

Add the following military times: 1355 + 0540

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
4 0
If its multiplcation
731700

if its addition 
1895

im sorry if im wrong but im just trying to help out and please correct me if ime wrong 

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1000 POINTS AND BRIANLEST
emmainna [20.7K]

Answer:

13,3,16

Step-by-step explanation:

7 0
3 years ago
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Simplify the expression (5x^2+13x-4)-(17x^2+7x-19)+(5x-7)(3x+1)
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5x²+13x-4-17x²-7x+19+15x²+5x-21x-7=
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8 0
3 years ago
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Critical points of x+5/x+2>0
Scorpion4ik [409]

Answer:

{-5, -2}

Step-by-step explanation:

In a case like this please use parentheses to remove ambiguities.  If I were to take your "x+5/x+2" literally, I'd have to write x             plus 5/x           plus 2.

I suspect that you actually meant (x + 5) / (x + 2), and will start with that.

First of all, this function is not defined at x = -5 or at x = -2.  Thus, -5 and -2 are critical points.  

Secondly, there may be one or more critical points beyond this.  To find out, we have to differentiate (x+5)/(x+2):

           (x + 2)(1) - (x + 5)(1)

f '(x) = ------------------------------

                  (x + 2)

Here it's clear that x cannot = -2, which would cause division by zero.

Thus, our critical values are {-5, -2}.

8 0
3 years ago
Complete the tables of values.<br> Q1) y = x2 - 2x + 4<br> x -1 0 1 2 3<br> y
sesenic [268]

Answer:

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Y-1 0 1 5 2

Step-by-step explanation:

hope it help

7 0
2 years ago
Find the value of Y<br> .....
vekshin1

Answer:

y = 6 \sqrt{3}  \: units

Step-by-step explanation:

In order to find the value of y, first we need to find the length of the perpendicular dropped from one of the vertices of the triangle to its opposite side.

By geometric mean theorem:

Length of the perpendicular

=\sqrt{9\times 3}

=\sqrt{27}\: units

Next, by Pythagoras theorem:

{y}^{2}  =  {9}^{2}  +  {( \sqrt{27} )}^{2}  \\  \\  {y}^{2}  = 81 + 27 \\  \\  {y}^{2}  = 108 \\  \\ y =  \sqrt{108}  \\  \\ y =  \sqrt{36 \times 3}  \\  \\ y =  \sqrt{ {6}^{2}  \times 3}  \\  \\ y = 6 \sqrt{3}  \: units

4 0
3 years ago
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