Answer:
A
Step-by-step explanation:
Answer:
Part 1) The volume of the paperweight is 
Part 2) The total surface area of the paperweight is 
Step-by-step explanation:
Part 1) what is the volume of the paperweight?
we know that
The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube
step 1
Find the volume of the pyramid
The volume of the pyramid is equal to

where
B is the area of the square base
H is the height of the pyramid


substitute

step 2
Find the volume of the cube
The volume of the cube is equal to


step 3
Find the volume of the paperweight

Part 2) what is the total surface area of the paperweight?
we know that
The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid
step 1
Find the surface area of 5 faces of the cube


step 2
Find the lateral area of the pyramid
![LA=4[\frac{1}{2}bh]](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7Dbh%5D)
![LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}](https://tex.z-dn.net/?f=LA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%288%29%285%29%5D%3D80%5C%20cm%5E%7B2%7D)
step 3
Find the total surface area of the paperweight

Answer: 
Step-by-step explanation:
<u>Given expression</u>
4x³ + 24x² - 288x
<u>Factorize 4x out from the expression</u>
4x · x² + 4x · 6x - 4x · 72
4x (x² + 6x - 72)
<u>Cross multiply to factorize the remaining polynomial expression</u>
<em>The meaning is to allow the factored product of the constant to add up to the first-degree term</em>
x 12
x -6
<u>Combine the result</u>

Hope this helps!! :)
Please let me know if you have any questions
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)
The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)
Answer: The system of inequalities would produce the region indicated on the graph is Option B