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Anettt [7]
3 years ago
6

Jon rides his bike 5 miles in 40 minutes Paul rides his bike 8 miles in 40 minutes if they continue at this rate how far will ea

ch person ride in one hour?
Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

6x² + 11x – 35 = 0, 2x²

– 4x – 2 = 0, 2x² – 64 = 0, x²

– 16 = 0, x² – 7x = 0, 2x² + 8x = 0

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Which expression shows the sum of a number and its additive inverse?A.–10 – 10B.10 – (–10)C.10 + (–10)D.–10 + (–10)
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The slope of the line in the graph is 4. Fill in the y intercept. Choose the correct equation in the form y = mx + b The y inter
nikitadnepr [17]

Answer:

\rm\implies y = 4x + 3

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u>

  • The slope of the line in the graph is 4.

And we need to find the equation of the line. On looking at the graph we see that , it cuts y axis at (0,3) .So the y Intercept of the equation is 3 .

<u>Slope</u><u> Intercept</u><u> Form</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = mx + c

<u>Substituting</u><u> the</u><u> respective</u><u> values</u><u> </u><u>:</u><u>-</u><u> </u>

\rm\implies y = 4*x + 3 \\\\\rm\implies y = 4x + 3

<u>Hence</u><u> the</u><u> </u><u>equation</u><u> of</u><u> </u><u>line </u><u>is </u><u>y </u><u>=</u><u> </u><u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>3 </u>

7 0
3 years ago
What is the flow rate of the air in the pipeline if the cross sectional area of a pneumatic pipeline is 0.01 m2 and the speed of
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Answer:

0.2 m³/s

Step-by-step explanation:

Applying,

Q = vA.............. Equation 1

Where Q = Flow rate of  air in the pipeline, v = flow velocity of the air in the pipeline, A = cross sectional area of the pneumatic pipeline.

From the question,

Given: v = 20 m/s, A = 0.01 m²

Substitute these values into equation 1

Q = 20(0.01)

Q = 0.2 m³/s

Hence the flow rate of air in the pipeline is  0.2 m³/s

7 0
3 years ago
what is the explicit formula for a sequence for which the first five terms are 0, 0, 1, 5, and 23? an = (n – 1)! – 1 an = (n – 1
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a_1=0;\ a_2=0;\ a_3=1;\ a_4=5;\ a_5=23\\\\Answer:\\\\a_n=(n-1)!-1\\becouse\\a_1=(1-1)!-1=0!-1=1-1=0\\a_2=(2-1)!-1=1!-1=1-1=0\\a_3=(3-1)!-1=2!-1=1\cdot2-1=2-1=1\\a_4=(4-1)!-1=3!-1=1\cdot2\cdot3-1=6-1=5\\a_5=(5-1)!-1=4!-1=1\cdot2\cdot3\cdot4-1=24-1=23
7 0
3 years ago
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