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Anettt [7]
3 years ago
6

Jon rides his bike 5 miles in 40 minutes Paul rides his bike 8 miles in 40 minutes if they continue at this rate how far will ea

ch person ride in one hour?
Mathematics
1 answer:
Darina [25.2K]3 years ago
3 0

Answer:

6x² + 11x – 35 = 0, 2x²

– 4x – 2 = 0, 2x² – 64 = 0, x²

– 16 = 0, x² – 7x = 0, 2x² + 8x = 0

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Find the length of the altitude drawn to the hypotenuse.the triangle is not drawn to scale
Marrrta [24]

Answer:

4√5

Step-by-step explanation:

Let's call it x

According to Euclidean theorem x^2 = 5×16

x^2= 80 and

x = 4√5

6 0
3 years ago
Need help with this please
Crazy boy [7]

Answer:

1. 2(k + 3)

2. 3. 75 + k

Step-by-step explanation:

1. 2x + 6

Since, 2 is a common factor of 2 and 6, we can take that common outside.

So, 2x + 6 = 2(x + 3)

Note that in the initial expression, this 2 was distributed to arrive at 2x + 6.

2. (1.5 + k) + 2.25

This is simple addition. We can simply remove the brackets to have:

1.5 + k + 2.25

Since, the like terms can be added, we will have:

1.5 + 2. 25 + k

= 3. 75 + k

8 0
3 years ago
When is it better to use a table in math
Galina-37 [17]

Answer:

in certain questions

Step-by-step explanation:

only use a table in Math when it is necessary. for example, when you are trying to find the coefficient.

3 0
3 years ago
Select the correct answer. Evaluate the following expression when x = -4 and y = 4. A. B. C. D.
andriy [413]

The value of given expression when x=-4 and y=4 is 1250.

The expression is missing in the question which is \dfrac{x^6-x}{4y}.

We have to solve it for x= -4 and y = 4.

Now putting the value of x and y we get,

\dfrac{x^6-x}{4y}=\dfrac{(-4)^6-(-4)}{4}

\dfrac{x^6-x}{4y}=\dfrac{4096+4}{4}

\dfrac{x^6-x}{4y}=1250

Hence the value of given expression when x=-4 and y=4 is 1250.

For more details follow the link:

brainly.com/question/11897796

3 0
2 years ago
Find the largest product the positive numbers x, y, and z can have if x+y +z 2 = 16
Vikki [24]
X = 4.33333333333
y = 5.33333333333
z = 6.33333333333

3 0
3 years ago
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