Answer:
Contradiction
Step-by-step explanation:
Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.
Answer:

or

Step-by-step explanation:
<u><em>The correct question is </em></u>
A landscaper needs 3 4/8 pounds of plant food. He has 1 1/4 pounds in his truck, and another 4/6 pound at his shop. How many more pounds of plant food does the landscaper need?
Let
x ----> the additional pounds of plant food needed for the landscaper
we know that
The additional pounds of plant food needed for the landscaper plus the pounds in his truck plus the pounds in his shop must be equal to the total pounds of plant food needed
so
The linear equation that represent this problem is

Convert mixed number to an improper fractions


Substitute in the expression above

solve for x
Multiply by (4*6) both sides to remove the fractions

Combine like terms left side

subtract 46 both sides


Divide by 24 both sides

simplify

Convert to mixed number

Answer:
I think so, but don't lose sight
Step-by-step explanation:
4x+ 5x - 5 +6 +4y^3- 2y^3- 5y^3
9x + 1 + 64y - 8y - 125y
9x + 1 - 69y
10 is the answer because using the Pythagorean theorem 6^2 + 8^2 = 100. The square root of 100 would be 10