Ask question

Ask question

All categories

3 years ago

10

Which are the characteristics of a maritime polar air mass? A. cold and humid air B. cold and dry air C. warm and humid air D. w

arm and dry air

2 answers:

Maksim231197 [3]3 years ago

6 0

It is b cold and dry air I hope it helps

Zarrin [17]3 years ago

5 0

I think it is a hope it helps

You might be interested in

Mariko has an 80:1 scale-drawing of the floor plan of her house. On the floor plan, the dimensions of her rectangular living roo

Crazy boy [7]

In order to get to the result we will need to use the scale and the numbers that are provided of the dimensions of the room.

The dimensions of the room on the floor plan are 17.8 inches by 21.2 inches. We first need to multiply these numbers with the scale:

17.8 x 80 = 1,424

21.2 x 80 = 1,696

Now that we got the real measures we need to multiply these two values in order to get to a result as in how many square inches is the room:

1,424 x 1696 = 2,425,104

Now we need to convert the square inches into square feet to get to the final result:

1 ft² = 144 in²

2,425,104 / 144 = 16,771.56

So we have a result of 16,771.56 square feet.

4 0

3 years ago

Cuando la natalidad supera la mortalidad se habla de:

Gnoma [55]

Answer:

Cuando la tasa de natalidad supera con creces la tasa de mortalidad, la población se dispara. Duplicar el tiempo es la cantidad de tiempo que tarda una cantidad en duplicarse y se utiliza en demografía para proyectar cambios futuros en el tamaño de la población.

5 0

2 years ago

2 1. Scattering cross-section of acrosol particles is 2.5E-12 m , absorption cross-section is 0.45E- .2 12 m Concentration of pa

Alona [7]

Answer:

$T = 3.23 \times 10^{-83}$

Explanation:

thickness of aerosol layer is 2.5 km

zenith angle is 40 degree

we know that

$\tau = \epsilon_{ext} . h$

where

$\epsilon_{ext} = N.\sigma_{ext}$

$\epsilon_{ext}$ is extinction coefficient

$\sigma_{ext}$ extiction cross section

N = Concentration

$\sigma_{ext} = (2.5 + 0.45)\times 10^{-12} m^2$

$= 2.95 \times 10^{-12} m^2$

$\epsilon_{ext} = 2\times 10^7 \times 2.95 \times 10^{-12} m^2 \times m^{-3}$

$= 5.9 \times 10^{-5} m^{1}$

$\tau = 5.9 \times 10^{-5} m^{-1} \times 2.5\times 10^3 m$

$= 14.75\times 10^{-2}$

transimiitance $T = e^{\frac{-\tau}{\mu}}$

$T = e^{\frac{- 14.75 \times 10^{-2}}{cos 40}}$

$T = 3.23 \times 10^{-83}$

6 0

3 years ago

Where does surface water collect if it does not flow to the ocean?

11111nata11111 [884]

Answer:

ponds, lakes, rivers, streams, springs, all types of places.

Explanation:

3 0

3 years ago

2. Which of these is a worldwide interconnected group?<br> Choose

vaieri [72.5K]

You need to show a picture to go with it because how are we suppose to know what to choose

8 0

3 years ago