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tiny-mole [99]
3 years ago
11

4) Dan had 199 dollars to spend on 7 books. After

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

The answer is that each book costs 26 dollars

Step-by-step explanation:

First we subtract 199 dollar from 7 =182

Then we divide 182 dollars to the seven book in order to find a unit =182/7=26

To prove this answer multiply 26 dollars than 7 books and see if the outcome is 182.Then subtract 199 from 182 and see if you got 17.

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Basile [38]

Step-by-step explanation:

m< AOC = 90°

m< AOB +m<BOC = 90°

6x-12+3x +30 = 90°

9x +18° = 90°

9x = 90- 18° = 72°

x = 8°

m<AOB =6(8)-12 = 48-12 = 36°

4 0
3 years ago
Read 2 more answers
Kamila buys a notebook for $1.59 and pens for $0.29 each. She spends $5.07.
emmasim [6.3K]

Answer:

12 pens

Step-by-step explanation:

Let the variable that can be used to determine the number of pens that Kamila bought be represented by n.

Price of a notebook = $1.59

Price a pen = $0.29

Total amount spent = $5.07

But,

1.59 + 0.29 n = 5.07

So that,

0.29 n = 5.07 - 1.59

0.29 n  = 3.48

n = \frac{3.48}{0.29}

  = 12

Therefore, Kamila bought 12 pens.

6 0
3 years ago
Make 24 using 1,2,2,7
alexdok [17]
7 times 2=14
14 times 2=24
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5 0
3 years ago
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Find two numbers the exact answer is between 8×684
ollegr [7]
 8 * 684 = 5472

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8 0
3 years ago
In the game of​ roulette, a player can place a ​$4 bet on the number 29 and have a 1/38 probability of winning. If the metal bal
creativ13 [48]

Answer:

The expected value of the game to the player is -$0.2105 and the expected loss if played the game 1000 times is -$210.5.

Step-by-step explanation:

Consider the provided information.

It is given that if ball lands on 29 players will get $140 otherwise casino will takes $4.

The probability of winning is 1/38. So, the probability of loss is 37/38.

Now, find the expected value of the game to the player as shown:

E(x)=(140)\times \frac{1}{38}+(-4)\times \frac{37}{38}

E(x)=\frac{140-148}{38}

E(x)=\frac{-8}{38}=-$0.2105

Hence, the expected value of the game to the player is -$0.2105.

Now find the expect to loss if played the game 1000 times.

1000×(-$0.2105)=-$210.5

Therefore, the expected loss if played the game 1000 times is -$210.5.

5 0
3 years ago
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