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Svetach [21]
3 years ago
10

class="latex-formula">
Mathematics
2 answers:
emmasim [6.3K]3 years ago
8 0

Answer:

x ≤ - \frac{1}{3}

Step-by-step explanation:

Given

3x + 14 ≤ 13 ( subtract 14 from both sides )

3x ≤ - 1 ( divide both sides by 3 )

x ≤ - \frac{1}{3}

Anna35 [415]3 years ago
6 0

Answer:

<h2>x≤-⅓</h2>

Step-by-step explanation:

<h3>to understand the solving steps</h3><h3>you need to know about:</h3>
  • inequality
  • PEMDAS
<h3>given:</h3>

3x+14≤13

<h3>to solve:</h3>

x

<h3>let's solve:</h3>

step - 1  \colon \: define

3x + 14 \leqslant 13

step  - 2 \colon \: subtract

3x  + 14 - 14 \leqslant 13 - 14

3x \leqslant  - 1

step - 3   \colon \: divide

\frac{3}{3} x \leqslant   - \frac{1}{3}

x \leqslant   - \frac{1}{ 3}

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Given the definitions of f (x) and g(x) below, find the value of (g • f)(9).
Stells [14]

9514 1404 393

Answer:

  (g·f)(9) = 496

Step-by-step explanation:

One way to do this is to find the values of g(9) and f(9).

  g(9) = (3x -1)x +14 = (3(9) -1)(9) +14 = 26(9) +14 = 248

  f(9) = -(9) +11 = 2

Then ...

  (g·f)(9) = g(9)·f(9) = 248·2

  (g·f)(9) = 496

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3 years ago
Solve 4|x + 5| + 8 = 24.
KIM [24]
Your answer would be C
6 0
2 years ago
1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?
Nookie1986 [14]

1. What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?


Point Slope form y − y1 = m(x − x1)


Y1: -7 x1:1 slope :-2/3


Y-(-7)=-2/3(x-1)

Y+7=-2/3(x-1)


2. What is the equation of a line, in point-slope form, that passes through (-2,-6) and had a slope of 1/3?


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M= -1-5/-3-4

M= -6/-7

M=6/7


So now slope:6/7, point (4,5)

Y-y1=m(x-x1)

Equation in point slope

Y-5=6/7(x-4)



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4 years ago
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olga55 [171]

Answer: r= 3.95

Explanation: A=πr2

5 0
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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