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Likurg_2 [28]
3 years ago
9

The senior classes at High School A and High School B planned separate trips to New York City. The senior class at High School A

rented and filled 12 vans and 11 buses with 303 students. High School B rented and filled 6 vans and 7 buses with 183 students. Each van and each bus carried the same number of students. How many students can a van carry? How many students can a bus carry?
Mathematics
1 answer:
Deffense [45]3 years ago
3 0

The van can carry 6 students and bus can carry 21 students.

Step-by-step explanation:

Given,

High School A: 12 vans and 11 buses with 303 students

High School B: 6 vans and 7 buses with 183 students

To find the number of students that a van and a bus can carry.

Let us take,

The van can carry x students and the bus can carry y students.

According to the problem,

12x+11y = 303 ------- (1)

6x+7y = 183 ------- (2)

Multiplying 2 with (2) and subtract (1) and (2) we get,

(12x+11y) - 2(6x+7y) = 303-2(183)

or, 12x+11y-12x-14y = 303-366

or, -3y = -63

or, y = 21

From (2) we get,

6x+7(21) = 183

or, 6x = 183-147

or, 6x = 36

or, x = 6

Hence,

The van can carry 6 students and bus can carry 21 students.

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explanation
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4 years ago
How many different ways can the letters of “football” be arranged
makvit [3.9K]
<h3>Answer:   10,080</h3>

Explanation:

There are 8 letters so there are 8! = 8*7*6*5*4*3*2*1 = 40,320 permutations of those letters. However, the letters "O" and "L" show up twice each, so we must divide by 2! = 2*1 = 2 for each instance this happens.

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3 years ago
Y= (x-9) (x+3)
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Answer:

y = x² − 6x − 27

Step-by-step explanation:

To distribute, you can use something called FOIL.  It stands for First, Outer, Inner, Last.

First, multiply the First term in each factor.

x · x = x²

Now multiply the Outer terms in each factor.

x · 3 = 3x

Next multiply the Inner terms in each factor.

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Finally, multiply the Last terms in each factor.

-9 · 3 = -27

Add them all up:

x² + 3x − 9x − 27

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