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scoundrel [369]
3 years ago
6

HELP ME I NEED HELLLPPP I AM A 6th grater if u ask HELLLPP ME

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

Multiply by 3;9

Step-by-step explanation:

9/3=3

12/4=3

18/6=3

27/n=3

N=9

You might be interested in
F(x)=4x+1 and g(x)=x^2-5find(f-g)(x)
Vinvika [58]

Answer:

<h2>-x²+4x +6</h2>

Step-by-step explanation:

Given f(x)=4x+1 and g(x)=x²-5

(f-g)(x) is derived by taking the difference of both functions

(f-g)(x) = f(x)-g(x)

(f-g)(x) = 4x+1 - (x²-5)

(f-g)(x)  = 4x+1-x²+5

(f-g)(x)  = -x²+4x +6

This gives the requires expression

4 0
3 years ago
How much money should be deposited today in an account that earns 6% compounded monthly so that it will accumulate to $1000000 (
aleksandr82 [10.1K]

Answer:

The principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

Step-by-step explanation:

Given

  • Accrued Amount A = $1000000
  • Interest rate r = 6% = 0.06
  • Time period t = 45 years
  • Compounded monthly n = 12

To determine:

  • Principle amount P = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

P\:=\frac{A}{\left(1\:+\:\frac{r}{n}\right)^{nt}}

substituting A = 1000000, r =  0.06, t = 45, and n = 12

P\:=\frac{1000000}{\left(1\:+\:\frac{0.06}{12}\right)^{12\cdot 45}}\:

    =\frac{1000000}{1.005^{540}}

P = 67659.17 $

Therefore, the principal investment required to get  a total amount of $ 1,000,000.00  from compound interest at a rate of 6% per year  compounded 12 times per year  over 45 years  is $ 67,659.17.

7 0
3 years ago
plz help whats the answer to this question !!! calculate the mass of a gold bar that is 18.00cm long, 9.21cm wide, and 4.45cm hi
erik [133]

We have to find the mass of the gold bar.

We have gold bar in the shape of a rectangular prism.

The length, width, and the height of the gold bar is 18.00 centimeters, 9.21 centimeters, and 4.45 centimeters respectively.

First of all we will find the volume of the gold bar which is given by the volume of rectangular prism:

Volume of the gold bar = length \times width\times height

Plugging the values in the equation we get,

Volume of the gold bar =18.00 \times 9.21 \times 4.45= 737.721cm^3

Now that we have the volume we can find the mass by using the formula,

Mass= density \times volume

The density of the gold is 19.32 grams per cubic centimeter. Plugging in the values of density and volume we get:

Mass = 19.32\times 737.721=14252.769 grams

So, the mass of the gold bar is 14252.769 grams

7 0
3 years ago
In 2000 the total amount of gamma ray bursts was recorded at 6.4 million for a city. In 2005, the same survey was made and the t
ratelena [41]

Let's assume

It started in 2000

so, t=0 in 2000

P_0=6.4million

we can use formula

P(t)=P_0 e^{rt}

we can plug value

P(t)=6.4 e^{rt}

In 2005, the same survey was made and the total amount of gamma ray bursts was 7.3 million

so, at t=2005-2000=5

P(t)=7.3 million

we can plug value and then we can solve for r

7.3=6.4 e^{r*5}

r=0.02632

now, we can plug back

P(t)=6.4 e^{0.02632t}

now, we have

P(t)=1 billion =1000 million

so, we can set it and then we can solve for t

1000=6.4 e^{0.02632t}

t=191.924

approximately

t=192

Year is 2000+192

year is 2192................Answer

4 0
3 years ago
A farmer sells an average of 15 bushels of corn
S_A_V [24]

Answer:

he goes from 15 to 90 ears of corn in 6 days

Step-by-step explanation:

15*6=90

8 0
3 years ago
Read 2 more answers
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