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scoundrel [369]
3 years ago
6

HELP ME I NEED HELLLPPP I AM A 6th grater if u ask HELLLPP ME

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

Multiply by 3;9

Step-by-step explanation:

9/3=3

12/4=3

18/6=3

27/n=3

N=9

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Svetlanka [38]

Answer:

area of rectangle=l×b=2.4×5.8=13.92cm²

6 0
3 years ago
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If you break the illustration below into four groups of stars to smiley faces, what would be the ratio?
klio [65]

Answer:

A

Step-by-step explanation:

there are 3 stars to 1 smiley face

im sorry if I was wrong.

8 0
2 years ago
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We are standing on the top of a 1680 ft tall building and throw a small object upwards. At every second, we measure the distance
MAVERICK [17]

Answer:

a) The height of the small object 3 seconds after being launched is 2304 feet.

b) The small object ascends 128 feet between 5 seconds and 7 seconds.

c) The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) The object will take 21 seconds to hit the ground.

Step-by-step explanation:

The correct formula for the height of the small object is:

h(t) = -16\cdot t^{2}+256\cdot t+1680 (1)

Where:

h - Height above the ground, measured in feet.

t - Time, measured in seconds.

a) The height of the small object at given time is found by evaluating the function:

h(3\,s)= -16\cdot (3\,s)^{2}+256\cdot (3\,s)+1680

h(3\,s) = 2304\,ft

The height of the small object 3 seconds after being launched is 2304 feet.

b) First, we evaluate the function at t = 5\,s and t = 7\,s:

h(5\,s)= -16\cdot (5\,s)^{2}+256\cdot (5\,s)+1680

h(5\,s) = 2560\,s

h(7\,s)= -16\cdot (7\,s)^{2}+256\cdot (7\,s)+1680

h(7\,s) = 2688\,s

We notice that the small object ascends in the given interval.

\Delta h = h(7\,s)-h(5\,s)

\Delta h = 128\,ft

The small object ascends 128 feet between 5 seconds and 7 seconds.

c) If we know that h = 2640\,ft, then (1) is reduced into this second-order polynomial:

-16\cdot t^{2}+256\cdot t-960=0 (2)

All roots of the resulting equation come from the Quadratic Formula:

t_{1} = 10\,s and t_{2}= 6\,s

The object will take 6 and 10 seconds after launch to reach a height of 2640 feet.

d) If we know that h = 0\,ft, then (1) is reduced into this second-order polynomial:

-16\cdot t^{2}+256\cdot t +1680 = 0 (3)

All roots of the resulting equation come from the Quadratic Formula:

t_{1} = 21\,s and t_{2} = -5\,s

Just the first root offers a solution that is physically reasonable.

The object will take 21 seconds to hit the ground.

8 0
2 years ago
The numbers 7, 11, 12, 13, 14, 18, 21, 23, 27, and 29 are written on separate cards, and the cards are placed on a table with th
Sophie [7]

there are a total of 10 cards

there are 3 cards with even numbers

 so you have a 3/10 probability of picking an even n umber

4 0
3 years ago
Read 2 more answers
Need help ASAP please not links please
Llana [10]

Answer:

a) 22:24 simplified the answer is 11:12

b) 21:81 simplified the answer is 7:27

Step-by-step explanation:

not sure how you were taught but those could also be

a)  \frac{22}{24} or simplified the answer is \frac{11}{12}

b) \frac{21}{81} or simplified the answer is  \frac{7}{27}

7 0
2 years ago
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