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Debora [2.8K]
3 years ago
12

a ribbion is 3 2/3 yards long. Mae needs to cut the ribbion into pieces that are 2/3 yard long.how much ribbion will be left aft

er she cuts these pieces
Mathematics
1 answer:
Lemur [1.5K]3 years ago
7 0
To answer this question you need to divide to get the number of pieces and then multiply whats leff by 3 2/3.

Divide 3 2/3 by 2/3. There are a few ways to do this but I am going to turn 3 2/3 into an improper fraction and then divide.

So 3\frac{2}{3} = \frac{11}{3}
Now divide
\frac{\frac{11}{3}}{\frac{2}{3}}
\frac{11}{3} \times \frac{3}{2} = \frac{11}{2} = 5\frac{1}{2} = 5.5

We can see she can get 5.5 pieces at 2/3. So .5 is going to be left over so we ask our self, what is .5 of 3 2/3? We times .5 by 3 2/3 = 1.83 yards left. If you want it into a fraction, it would be 1\frac{83}{100} yards left
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Answer:

The solution to the inequality is:

\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}

The solution graph is also attached below.

Step-by-step explanation:

Given

We are given the expression

\frac{1}{3}x+5>10

To determine

Solve for x

Given the expression

\frac{1}{3}x+5>10

Subtract 5 from both sides

\frac{1}{3}x+5-5>10-5

Simplify

\frac{1}{3}x>5

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3\cdot \frac{1}{3}x>5\cdot \:3

Simplify

x>15

Thus, we conclude that:

x>15

Therefore, the solution to the inequality is:

\frac{1}{3}x+5>10\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>15\:\\ \:\mathrm{Interval\:Notation:}&\:\left(15,\:\infty \:\right)\end{bmatrix}

The solution graph is also attached below.

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Answer:

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Step-by-step explanation:

The real part does not have i as a multiplier. It is 23.3.

The imaginary part* is the coefficient of i: 44.

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* There is some disagreement as to whether the imaginary part includes i or not. One source says the imaginary part is the part that has i as a factor (44i). Another source says the imaginary part is the real number that multiplies i (44). Above, we have used the latter definition. Please consult your curriculum materials for the definition you should use.

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