Equation 2 is a square root function, kind of like half of a sideways parabola, Equation 3 is a parabola, and 4 is a cubic function (s-shaped). This leaves Equation 1, which is a line with a slope of 2 with a y-intercept at 7. So I'd say the answer is 1.
Downloaded Photomath it’s going to help you a lot
Hello there!
Yes, your solution is correct! A way to check it is replacing the value you found for x into x in the equation.
3(2-x) = 7 - 4x ⇒ 3(2-1) = 7 - 4(1)
And now solve 3(2-1) = 7 - 4(1).
3(1) = 7 - 4(1)
3 = 7 - 4
3 = 3
Since it is a true statement that 3 is equal to 3, it means your solution of x = 1 is correct. Good job! :)
Answer:
y = 3/2x (This should be the correct answer do to the fact the slope is 3/2 and the points on here are 1, 1 which would most likely mean the y-intercept is 0. So we don't need to write the y-intercept on this equation.
<span>Width = 6
Length = 30
We know the perimeter of a rectangle is simply twice the sum of it's length and width. So we have the expression:
72 = 2*(L + W)
And since we also know for this rectangle that it's length is 6 more than 4 times it's width, we have this equation as well:
L = 6 + 4*W
So let's determine what the dimensions are. Since we have a nice equation that expresses length in terms of width, let's substitute that equation into the equation we have for the perimeter and solve. So:
72 = 2*(L + W)
72 = 2*(6 + 4*W + W)
72 = 2*(6 + 5*W)
72 = 12 + 10*W
60 = 10*W
6 = W
So we now know that the width is 6. And since we have an expression telling us the length when given the width, we can easily determine the length. So:
L = 6 + 4*W
L = 6 + 4*6
L = 6 + 24
L = 30
And now we know the length as well.</span>
