Which angle is an exterior angle of the triangle?

Alik [6]

You will notice that 48°, x, and x lie upon a straight line. The sum of those angles must then be equal to 180°. Which means:

48+x+x=180

48+2x=180

2x=132

x=66°

7 0

3 years ago

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F(x)=3x-3 g(x) 3x^3+5 Find F(-3) and g(-2)

astra-53 [7]

Answer:

f(-3) = -12

g(-2) = -19

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 3x - 3

g(x) = 3x³ + 5

f(-3) is x = -3 for function f(x)

g(-2) is x = -2 for function g(x)

Step 2: Evaluate

f(-3)

Substitute in x [Function f(x)]: f(-3) = 3(-3) - 3
Multiply: f(-3) = -9 - 3
Subtract: f(-3) = -12

g(-2)

Substitute in x [Function g(x)]: g(-2) = 3(-2)³ + 5
Exponents: g(-2) = 3(-8) + 5
Multiply: g(-2) = -24 + 5
Add: g(-2) = -19

4 0

3 years ago

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Statistics Question. Use the Desmos graphing calculator to find the least-squares regression line for the dataset in the table:

Soloha48 [4]

Given:

The table of values.

To find:

The least-squares regression line for the data set in the table by using the desmos graphing calculator.

Solution:

The general form of least-squares regression line is:

$\hat{y}=mx+b$ ...(i)

Where, m is the slope and b is the y-intercept.

By using the desmos graphing calculator, we get

$m\approx 2.55,b\approx -6.435$

Substitute these values in (i).

$\hat{y}=(2.55)x+(-6.435)$

$\hat{y}=2.55x-6.435$

Therefore, the correct option is A.

8 0

3 years ago

Please help :( a to d, will give brainliest!!

____ [38]

Answer:

a) y=4x-3

b) y=-1/2x+4

c) y=-3x+8

d) y=5/3x-1

Step-by-step explanation:

y1-y2/x1-x2

Plug in the numbers and solve.

4 0

3 years ago

In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=

just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}$ Given

$\displaystyle 2) \text{ } m \angle PAB = 60$ Definition of equilateral.

$3)\text{ } m \angle QAC = 60$ Definition of equilateral.

$4)\text{ } m\angle PAB = m\angle QAC$ Substitution

$5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC$ Angle Addition

$\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC$ Angle Addition

$7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC$ Substitution

$\displaystyle 8)\text{ } m\angle PAC=m\angle QAB$ Substitution

$9)\text{ } PA=BA$ Definition of equilateral

$10)\text{ } AC=AQ$ Definition of equilateral

$\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ$ Side-Angle-Side Congruence*

$\displaystyle 12)\text{ } PC=BQ$ CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

6 0

3 years ago

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