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goldenfox [79]
3 years ago
13

Which One Will Round to 0.8 with tenths 0.841 0.45 0.55 0.738

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0

0.841 will round to 0.8 with tenths.


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The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.
OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when t=\frac{13}{2}

Step-by-step explanation:

From the information given, the equation of motion of the object is

s(t)= -16t^2+208t+156

For any equation of motion s(t), the instantaneous velocity at time t is given by

v(t)=\frac{ds}{dt}

(a) To find the object's velocity at t = 7, you must:

v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208

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v(7)=-32(7)+208=-224+208\\\\v(7)=-16

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}

Next, we substitute this value into the equation of motion to find the maximum height

s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832

The maximum height is 832 ft and it occurs when t=\frac{13}{2}

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the answer is d

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