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3 years ago

Solve for x 21x+6help please ?

2 answers:

8 0

If it equats to 0, then you send the six to where it equats as zro for it to bevome -6. It looks like this.
21x=-6.
Then send the 21 multiplied with the x to the other side. This time, it will act as division. This will look like this.
x=-6/21.
This simply means that x=-6/21.
Hope this helps.

OLEGan [10]3 years ago

4 0

subtract 6 from the 21x+6. Then divide by 21. The answer is going to be -6/21

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a pair of adjacent side of a rectangle are in the ratio 3 : 4 if its diagonal is 20 cm find the length of sides and hence the pe

lutik1710 [3]

Answer:

Step-by-step explanation:

Ratio=3:4

so,the pair of adjacent sides are 3x,4x

Pythagorean theorem,

$(3x)^{2}+(4x)^{2}=20^{2}\\9x^{2}+16x^{2}=400\\\\25x^{2}=400\\\\x^{2}=\frac{400}{25}\\\\ x^{2}=16\\\\x=\sqrt{16}\\\\x=4\\\\length=4x=4*4=16cm\\\\breadth=3x=3*4=12cm\\\\Perimeter=2*(l+b)\\\\=2*(16+12)=2*28\\\\=56cm$

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3 years ago

If r=1 and 0=5pi/6 what is the approximate arc length?

dem82 [27]

Answer:

B. 2.618 units

Step-by-step explanation:

the arc length = (5π/6) / 2π × 2×3.14×1

= 5/12 × 6.28

= 31.4/ 12

= 2.618 units

5 0

3 years ago

Read 2 more answers

A car goes 400 miles on 10 gallons of

Olenka [21]

Answer:

A. 1200

Step-by-step explanation:

Since 10 times 3 is 30, then 400 times 3 is 1200. Hope I helped!

4 0

4 years ago

A rectangular cake has a length of 22 1/2 inches and a width of 10 inches. How many whole, square pieces of cake with side lengt

faltersainse [42]

Well, we need to find the area of the cake. 22.5 times 10 is 225. That is the area then we need to find the area of each piece of cake. 2.5 times 2.5 is 6.26.
so divide the area of the cake by the area of each piece to find how many pieces can be cut.
225/6.25=36 36 pieces of cake can be cut from the cake

5 0

4 years ago

Your Turn<br>Find the infinite geometric sum of -144 +24 - 4 + ...

vlada-n [284]

Answer:

$-123\dfrac{3}{7}$

Step-by-step explanation:

Find the infinite geometric sum of -144 +24 - 4 + ...

The sum of infinite geometric sequence is

$S=\dfrac{b_1}{1-r},$

where $b_1$ is the first term and $r$ is the common ratio.

In your case,

$b_1=-144,\\ \\b_2=24,\\ \\b_3=-4,\\ \\r=\dfrac{b_2}{b_1}=\dfrac{24}{-144}=-\dfrac{1}{6}\\ \\ \bigskip\ \bigskip\ \bigskip =\dfrac{b_3}{b_2}=\dfrac{-4}{24}=-\dfrac{1}{6}$

So, the sum is

$S=\dfrac{-144}{1-\left(-\dfrac{1}{6}\right)}=\dfrac{-144}{1+\dfrac{1}{6}}=-\dfrac{144}{\dfrac{7}{6}}=-\dfrac{864}{7}=-123\dfrac{3}{7}$

4 0

3 years ago