B and C
0+11= +11
0-11= -11
Hope this helps
The mean and range for class A are 84.4 and 20 while the mean and range for class B are 83.6 and 8. Class B is more consistant then class A.
<h3>How to calculate the mean?</h3>
We can see from the data that the consistency of class B is more becuase the repeatation of the same score is more in class B then class A and the range of class B is also less then the class A.
It should be noted that mean simply means average. It's the addition of the numbers divided by the total numbers.
In this case, the computation will be:
Class A: Mean = 422/5= 84.4.
Range: 94-74 = 20
Class B: Mean = 418/5 = 83.6.
Range= 88-80 = 8
Learn more about mean on:
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11 x 3 3/4 = 41 1/4 (41.25)
10 1/2 x 0.55 = 5.775
41.25 + 5.775 = 47.025
100 - 47.025 = $52.975 her change
Hope it helps!
Answer:
x= 62
y= 54
Step-by-step explanation:
Step one:
given data
let the numbers be x and y and the larger be x the smaller be y
The difference between two numbers is 8
x-y= 8-----------1
If the larger is subtracted from three times the smaller, the difference is 100
3y-x=100------------2
from eqn 1, x= 8+y
put this in eqn 2
3y-(8+y)=100
3y-8-y=100
collect liker terms
3y-y-8=100
2y=108
y= 54
put y= 54 in eqn 1
x-y=8
x-54= 8
x= 8+54
x=62
What we can say with a good deal of certainty is that our sample is biased towards the higher spectrum and that the real value of the mean for our population is lower than the obtained value of our sample. If this is true, we should expect for the standard deviation to be higher than in the population.
