Answer:
a) 32
b) 67.613
Step-by-step explanation:
<em><u> In Game 3, Emerson struck out 42 times in 140 times at-bat.</u></em>
<em><u>Part A</u></em>
<em><u>Drag numbers to complete the proportion to represent the percent of strikeouts per at-bats.</u></em>
<em><u>Numbers may be used once or not at all.</u></em>
<em><u /></em>
<em><u>Part B</u></em>
<em><u>What percentage of times at bat did Emerson actually hit the ball?</u></em>
Part A
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
strikeouts : times
112: 350
p:100
Using cross product rule
p/100= 112/350
p * 350= 112*100
or p= 11200/350= 32
It means that there were 32 strikeouts if 100 times were bat at hits.
Part B:
Total number of strikeouts= 30+40+42= 112
Total number of at bats = 90+120+140= 350
But we need the percentage of times at bat hit
Therefore
Hits= times - strikeouts= 350-112= 238
Percentage = 238/352*100= 67.613
Check
The above answers are correct because
100-32 = 68
68 ≅ 67.613
Answer:
<h2>8</h2>
Step-by-step explanation:
6x = 48 then x = 48/6 then = 8.
:)
Answer:
Option A. 5
Step-by-step explanation:
From the question given above, the following data were obtained:
First term (a) = –3
Common ratio (r) = 6
Sum of series (Sₙ) = –4665
Number of term (n) =?
The number of terms in the series can be obtained as follow:
Sₙ = a[rⁿ – 1] / r – 1
–4665 = –3[6ⁿ – 1] / 6 – 1
–4665 = –3[6ⁿ – 1] / 5
Cross multiply
–4665 × 5 = –3[6ⁿ – 1]
–23325 = –3[6ⁿ – 1]
Divide both side by –3
–23325 / –3 = 6ⁿ – 1
7775 = 6ⁿ – 1
Collect like terms
7775 + 1 = 6ⁿ
7776 = 6ⁿ
Express 7776 in index form with 6 as the base
6⁵ = 6ⁿ
n = 5
Thus, the number of terms in the geometric series is 5.
Answer: It's D 64(x-8)2 + 12y2 < 144 on Edge
Step-by-step explanation:
