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Mama L [17]
3 years ago
11

-5(3m+6)= -3(4m - 2)

Mathematics
2 answers:
algol133 years ago
4 0
-15m -30 = -12m +6
3m = 36
m= 36/3 =12
siniylev [52]3 years ago
4 0

Answer:

m=-12

Step-by-step explanation:

−5(3m+6)=−3(4m−2)

−15m−30=−2m+6

−15m−30+12m=−12m+6+12m

-3m-30=6

-3m-30+30=6+30

-3=36

-3/-3=30/-3

m=-12



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Answer:

5

Step-by-step explanation:

Use Pythagorean’s theorem

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16 + 9 = c squared

25 = c squared

5 = c

8 0
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3 0
4 years ago
What is the interval notation for {x|x€ R, -2<x<6}​
Firdavs [7]

Answer:

\large\boxed{\{x|x\in\mathbb{R},\ -2

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3 0
4 years ago
A) The sixth term of an AP is twice the 3rd term and the first term is 3. Find the common
dangina [55]

Answer:

Step-by-step explanation:

The nth term of an AP is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

Sixth term

T6 = a+(6-1)d

T6 = a+5d

Third term;

T3 = a+(3-1)d

T3 = a+2d

If the sixth term of an AP is twice the 3rd term, then

a+5d = 2(a+2d)

a+5d = 2a+4d

Given a = 3

3+5d = 2(3)+4d

5d-4d = 6-3

d = 3

Common difference is 3

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T10 = a+9d

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T10 = 30

Hence the tenth term is 30

7 0
3 years ago
Find the product of z1 and z2, where z1 = 2(cos 80° + i sin 80°) and z2 = 9(cos 110° + i sin 110°)
nekit [7.7K]
ANSWER

z_1 z_2=18( \cos( 190 \degree  )  + i \sin( 190 \degree) )


EXPLANATION

The given complex numbers are;

z_1 = 2( \cos(80 \degree)  + i \sin(80 \degree) )

and


z_2= 9( \cos(110 \degree)  + i \sin(110 \degree) )


Recall the binominal identity for complex numbers in polar form.



z_1 z_2=r_1 r_2( \cos( \theta_1 +\theta_2)  + i \sin(\theta_1 +\theta_2) )



We apply this property to obtain,


z_1 z_2=2 \times 9( \cos( 80 \degree +  110 \degree  )  + i \sin(80 \degree +  110 \degree) )



z_1 z_2=18( \cos( 190 \degree  )  + i \sin( 190 \degree) )

4 0
4 years ago
Read 2 more answers
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