Evaluate 2w-9 for w=-2

Solve for x <br><br> 1−6x = −17

Alex_Xolod [135]

Answer:

x = 3

Step-by-step explanation:

1 - 6x = - 17 ( subtract 1 from both sides )

- 6x = - 18 ( divide both sides by - 6 )

x = 3

5 0

3 years ago

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A parking lot has seventy-eight parking spaces numbered from 1 to 78. There are no cars in the parking lot when Jillian pulls in

polet [3.4K]

Answer:

49/78

Step-by-step explanation:

Probability calculates the likelihood of an event occurring. The likelihood of the event occurring lies between 0 and 1. It is zero if the event does not occur and 1 if the event occurs.

For example, the probability that it would rain on Friday is between o and 1. If it rains, a value of one is attached to the event. If it doesn't a value of zero is attached to the event.

probability that the number on the parking space where she parks is greater than or equal to 30 = numbers greater than or equal to 30 / total numbers

49 / 78

6 0

3 years ago

How are subtracting and adding intigers related

Llana [10]

Answer:

Adding integers means adding integers with the same signs, while subtracting integers means adding the integers of opposite signs.

Step-by-step explanation:

5 0

4 years ago

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Carlos is analyzing the results of a recent scientific study about gravity. Scientists recorded that the experimental value of g

ASHA 777 [7]

Answer:

The answer is 4.38.

Step-by-step explanation:

You take the experimental value and subtract the accepted value from it. then take that and divide it by the accepted value. When you get your you move the decimal point and round if needed.

8 0

3 years ago

The drag Prevnar is a vaccine meant to prevent meningitis. It is typically administered to infants between 12 and 15 months of a

Fed [463]

Answer:

The pvalue of the test is 0.0058 < 0.01, which means that there is significant evidence to conclude the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135.

Step-by-step explanation:

Test if the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135

This means that the null hypothesis is:

$H_{0}: p = 0.135$

And the alternate hypothesis is:

$H_{a}: p \neq 0.135$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.135 is tested at the null hypothesis:

This means that $\mu = 0.135, \sigma = \sqrt{0.135*0.865}$

Of the 710 infants,121 experienced a loss of appetite.

This means that $n = 710, X = \frac{121}{710} = 0.1704$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.1704 - 0.135}{\frac{\sqrt{0.135*0.865}}{\sqrt{710}}}$

$z = 2.76$

Pvalue of the test and decision:

The pvalue of the test is the pobability that the population proportion differs from the tested proportion by at least 0.1704 - 0.135 = 0.0354, which is P(|z| > 2.76). This probability is 2 multiplied by the pvalue of z = -2.76.

Looking at the z-table, z = -2.76 has a pvalue of 0.0029

2*0.0029 = 0.0058

The pvalue of the test is 0.0058 < 0.01, which means that there is significant evidence to conclude the proportion of infants who receive Prevnar and experience of a loss of appetite is different from 0.135.

7 0

3 years ago