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2 years ago

8

What fraction is greater 2/9 or 1/2?

1 answer:

IRINA_888 [86]2 years ago

6 0

Answer:

1/2

Step-by-step explanation:

2 divided by 9 is .2222

1 divided by 2 is .5

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Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

2 years ago

Which of the following statements best describes the location of −(−2) on a number line? It is 2 units to the right of 0. It is

ivolga24 [154]

Let say x = -(-2) where x is the distance of number on number line from 0.
x = -(-2)
x = +2.
Since +2 is positive quantity, positive quantities are written to the right of 0 on number line.
Hence it is 2 units to the right of 0.

3 0

3 years ago

The data show the traveler spend- ing in billions of dollars for a recent year for a sample of the states. Find the range, varia

Svetllana [295]

Solution :

Given data :

20.1 33.5 21.7 58.4 23.2 110.8 30.9

24.0 74.8 60.0

n = 10

Range : Arranging from lowest to highest.

20.1, 21.7, 23.2, 24.0, 30.9, 33.5, 58.4, 60.0, 74.8, 110.8

Range = low highest value - lowest value

= 110.8 - 20.1

= 90.7

Mean = $\frac{\sum x}{n}$

$=\frac{20.1+21.7+23.2+24.0+30.9+33.5+58.4+60.0+74.8+110.8}{10}$

$=\frac{457.4}{10}$

$=45.74$

Sample standard deviation :

$S=\sqrt{\frac{1}{n-1}\sum(x-\mu)^2}$

$S=\sqrt{\frac{1}{10-1}(20.1-45.74)^2+(21.7-45.74)^2+(23.2-45.74)^2+(24.0-45.74)^2+(30.9-45)^2}$

$\sqrt{(33.5-45.74)^2+(58.4-45.74)^2+(60.0-45.74)^2+(74.8-45.74)^2+(110.8-45.74)^2}$

$S=\sqrt{\frac{1}{9}(657.4+577.9+508.0+472.6+220.2+149.8+160.2+203.3+844.4+4232.8)}$ $S=\sqrt{\frac{1}{9}(8026.96)}$

$S=\sqrt{891.88}$

S = 29.8644

Variance = $S^2$

$=(29.8644)^2$

= 891.8823

6 0

2 years ago

(0) 14 -7 0<br> | () 14 - 7 0

lyudmila [28]

Answer:

What is the question.

5 0

3 years ago

Find the slope and y-intercept. from the equation then graph the line . plsss helppp

djverab [1.8K]

Answer:

slope = -1. y int = (0, -3)

Step-by-step explanation:

look in this equation format

y=mx+b

m= slope

b= y int

y and x = a coordinate on the line

6 0

2 years ago