1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
antoniya [11.8K]
2 years ago
5

The University of Metropolis requires its students to pass an examination in college-level mathematics before they can graduate.

The students are given three chances to pass the exam; 61% pass it on their first attempt, 63% of those that take it a second time pass it then, and 48% of those that take it a third time pass it then. (Assume that all students who do not pass the first or second time elect to take the test again.) What percent of the students take the test three times? (Round your answer to one decimal place.)
Mathematics
1 answer:
Alborosie2 years ago
6 0

Answer:

  14.4%

Step-by-step explanation:

Of the 39% who fail the first exam, 37% fail a second time. Those are the ones who take it 3 times:

  0.39 × 0.37 = 0.1443 ≈ 14.4%

You might be interested in
What is the decimal that is equivalent to the expression 3 * 100 + 7 * 10 + 4 * 1 + 6 * 0.01 + 1 * 0.001
barxatty [35]
I believe it is 0.0318
5 0
2 years ago
The dimensions of a rectangle can be given by x+7 and x+2. If the area of the rectangle is 66 square inches, what are the dimens
Nadusha1986 [10]

to solve  for the dimensions (x+7)(x+2)=66,

we can first use the foiling method to simplify the left side.

x^2 + 2x + 7x + 14 = 66

x^2 + 9x + 14 = 66

now, subtract 66 from both sides.

x^2 + 9x - 52 = 0

now, split this into two parentheses.

(x + 13)(x - 4)

since the root of -13 would give you negative values, x=4. This means that the dimensions of the rectangle are 11 and 6.

7 0
3 years ago
Help pls I will give brainly points!!!
Angelina_Jolie [31]

Answer:

A

Step-by-step explanation:

R+65=135.

7 0
2 years ago
Read 2 more answers
You buy hamburgers at a fast food restaurant. A hamburger costs $0.49. You must have at most $3 to spend. Write an inequality fo
KIM [24]

Answer:

x ≤  6.12

Step-by-step explanation:

If the cost of 1 hamburger in a restaurant is $0.49, the amount of hamburger $3 can buy is expressed as shown .

$0.49 = 1

$3 ≤ x (since you have maximum of $3 to spend. It cant be more than that)

cross multiply to find the expression for x.

$0.49 * x  ≤  $3 * 1

$0.49x  ≤  $3

Divide both sides by $0.49

$0.49x/$0.49  ≤  $3/$0.49

x ≤  $3/$0.49

x ≤  6.12

The number of hamburgers you can buy is represented by the inequality x ≤  6.12

4 0
2 years ago
Lalala usa test prep heeeeeheheheheehhheheeehheh
Contact [7]

Answer:

:Dd

Step-by-step explanation:

Eh lalsaaaaaaa salaaaa

8 0
3 years ago
Read 2 more answers
Other questions:
  • A bus travels at a constant speed. The following table shows the distance the bus travels (in kilometers) over a period of time
    9·2 answers
  • Help me please ?????????
    10·1 answer
  • Vicky jogged 2.75 miles in .5 hour. what was her average rate of speed in miles?
    14·2 answers
  • The length of a rectangle is 6 units and its width is 4 units. What is the approximate length of the diagonal of the rectangle?
    11·1 answer
  • When sodium azide is activated in an automobile airbag, nitrogen gas and sodium are produced according to the following equation
    5·1 answer
  • What is the difference in the steps you take to evaluate (-7)2 and -72 ? What is the
    13·1 answer
  • Ken predicts that the average temperature will be −5°C in December. If he predicts the temperature will rise 6°C in January and
    14·1 answer
  • At Randy's Market, you can buy a dezen ears of corn for $3.00. At that rate, bem
    10·1 answer
  • Which number is rational?<br><br> A. -3 1/2<br> B. sqrt 5<br> C. Pi<br> D. 9.23157 ...
    8·1 answer
  • if you don't know the answer to one of the problems you can just answer how every many you know and btw ill mark you!!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!