Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of points. Mike has

Question

vladimir1956 [14]

2 years ago

5

Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of points. Mike has

twice the total number of points decreased 201. how many points do they have altogether?

Mathematics

1 answer:

elena-s [515] · Answer 1 · 2022-01-17T12:05:15+03:00

Answer:
129 points
Step-by-step explanation:
Let L and C represent the scores of Luke and Caleb, respectively.
L = 2C -15 . . . . . Luke scored 15 less than twice the number Caleb did
L +C = 201 . . . . . they scored 201 points altogether
Add twice the second equation to the first:
2(L +C) + (L) = 2(201) + (2C -15)
3L +2C = 387 +2C . . . . simplify
3L = 387 . . . . . . . . . . . . .subtract 2C
L = 387/3 = 129 . . . . . . .divide by 3
Luke scored 129 points.