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vladimir1956 [14]
3 years ago
5

Caleb and Mike both score the same amount of points in a game. Caleb has fifteen less than the total number of points. Mike has

twice the total number of points decreased 201. how many points do they have altogether?
Mathematics
1 answer:
elena-s [515]3 years ago
3 0
Answer:
129 points
Step-by-step explanation:
Let L and C represent the scores of Luke and Caleb, respectively.
L = 2C -15 . . . . . Luke scored 15 less than twice the number Caleb did
L +C = 201 . . . . . they scored 201 points altogether
Add twice the second equation to the first:
2(L +C) + (L) = 2(201) + (2C -15)
3L +2C = 387 +2C . . . . simplify
3L = 387 . . . . . . . . . . . . .subtract 2C
L = 387/3 = 129 . . . . . . .divide by 3
Luke scored 129 points.
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Convert 55°44'33" to decimal degree form. Round your answer to four decimal places.​
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Answer:

55,7425

Step-by-step explanation:

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Step-by-step explanation:

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kifflom [539]
5x + 60y = 35

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5(1.5-y) + 60y = 35

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divide both sides by 55 to solve for  y

y = 27.5 / 55 = 0.5

now substiute 0.5 for y in the 2nd equation:

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