d = 3 , a₁₂ = 40 and S = 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
The general equation of the circle is expressed as (x-h)2 + (y-k)2 = r2 where (h,k) is the center of the circle. we are are given the center of the circle at (0,0) so the expression is simplified to <span>(x)2 + (y)2 = r2. given the other point, r2 is equal to 41. hence the final equation is x2 + y2 = 41</span>
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Answer:
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Step-by-step explanation:
Answer:
Statement 2 (The ages of the Stars are the most dispersed from the team’s mean).
Step-by-step explanation:
Standard deviation is one way to measure the average of the data by determining the spread of the data. It actually explains how much the observation points are further away from the mean of the data. Higher the standard deviation, higher the spread of the data and higher is the uncertainty. This means that the team with the highest standard deviation will have the most dispersion. In this case, the standard deviation of 4.1 is the largest number, therefore, the statement "The ages of the Stars are the most dispersed from the team’s mean." is true i.e. the option 2!!!