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3 years ago

The area of a rectangle is 70 in2 and the length of the rectangle is 3 in longer than the width

Mathematics

2 answers:

kolezko [41]3 years ago

6 0

Answer:

w(w+3)= 70

hope it helps.

vodka [1.7K]3 years ago

4 0

A= 70 in2
W= x
L= x+3

W = 7
L= 10

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Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24

S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

$\frac{4}{3}=\frac{32}{d}$

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable $d$ and see if it satisfies the equation.

1) $d=22$

$\frac{4}{3}=\frac{32}{22}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 2}{22\div 2}$

$\frac{4}{3}=\frac{16}{11}$

The above statement can never be true and hence 22 is not a solution.

2) $d=23$

$\frac{4}{3}=\frac{32}{23}$

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

3) $d=24$

$\frac{4}{3}=\frac{32}{24}$

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

$\frac{4}{3}=\frac{32\div 8}{24\div 8}$

$\frac{4}{3}=\frac{4}{3}$

The above statement is always true and hence 24 is a solution.

4) $d=25$

$\frac{4}{3}=\frac{32}{25}$

The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

4 0

2 years ago

I have two and one half squares and i want to divide them by one fourth. How many pieces would i have?

Nutka1998 [239]

2+½, is just 2½, now divided by 1/4.

let's first convert the mixed fraction to improper, and then divide.

$\bf \stackrel{mixed}{2\frac{1}{2}}\implies \cfrac{2\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{5}{2}}
\\\\[-0.35em]
~\dotfill\\\\
\cfrac{5}{2}\div \cfrac{1}{4}\implies \cfrac{5}{2}\cdot \cfrac{4}{1}\implies \cfrac{5}{1}\cdot \cfrac{4}{2}\implies 5\cdot 2\implies 10$