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3 years ago

Solve the equations. Show the solution sets on a number line. Check your answers. c 9k+3 =−4

Mathematics

2 answers:

Naddika [18.5K]3 years ago

8 0

Answer:

k = -7/9

Step-by-step explanation:

9k + 3 = -4

9k = -7

k = -7/9

On the number line just make a closed circle at -7/9. No line would be drawn, just the dot

-7/9 would be between 0 and -1, closer to -1

motikmotik3 years ago

8 0

Answer:

k = -7/9

Step-by-step explanation:

If the equation is, 9k + 3 = -4, then;

9k =-4-3,

9k =-7,

k=-7/9

and on a number line just show a point with value -7/9, there is no inequality here

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3 years ago

write an equation to represent"three consecutive integers is 12 less than 4 times the middle integer'

Sever21 [200]

Consider that the three consecutive integers are:

least integer = n

middle integer = n + 1

greatest integer = n + 2

THe expression "three consecutive integers is 12 less than 4 times the middle integer" can be written as follow:

n + (n + 1) + (n + 2) = 4(n +1) - 12

In order to find the numbers, proceed as follow:

n + (n + 1) + (n + 2) = 4(n +1) - 12 cancel parenthesis

n + n + 1 + n + 2 = 4n + 4 - 12 simplify like terms

3n + 3 = 4n - 8 subtract 4n and 3 both sides

3n - 4n = - 8 - 3

-n = -11

n = 11

Hence, the three consecutive integers are:

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5 0

1 year ago

A probability distribution for a random variable Y is given by P(Y=y)=cy, for y=1,2,4,5 and c is a constant. Find E(Y), the expe

Dahasolnce [82]

Answer:

$c(1+2+4+5) =1$

$c =\frac{1}{12}$

Now we can find the expected value with this formula:

$E(Y) =\sum_{i=1}^n Y_i P(Y_i) =\sum_{i=1}^n cy_i *y_i = cy^2_i$

And replacing we got:

$E(Y) = \frac{1}{12} (1^2 + 2^2 + 4^2 +5^2) = \frac{46}{12}= \frac{23}{6}$

Step-by-step explanation:

For this case we know the following probability mass function given:

$P(y) = cy , y= 1,2,4,5$

For this case we need to satisfy the following condition in order to have a probability distribution function:

$\sum_{i=1}^n P(y_i) =1$

And we have this:

$c(1+2+4+5) =1$

$c =\frac{1}{12}$

Now we can find the expected value with this formula:

$E(Y) =\sum_{i=1}^n Y_i P(Y_i) =\sum_{i=1}^n cy_i *y_i = cy^2_i$

And replacing we got:

$E(Y) = \frac{1}{12} (1^2 + 2^2 + 4^2 +5^2) = \frac{46}{12}= \frac{23}{6}$

6 0

3 years ago