Answer:
<h2>x = 90°</h2><h2 />
Step-by-step explanation:
diagonal line = 180 = x + 90
180 - 90 = x
90 = x
therefore, x = 90°
Answer:
25
Step-by-step explanation:
Given
37 - (9 + 4) + 6 ÷ 6 ← evaluate parenthesis
= 37 - 13 + 6 ÷ 6 ← perform division
= 37 - 13 + 1 ← evaluate from left to right
= 24 + 1
= 25
Answer:
-2x³ - 14x² + 7x - 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
(3x³ - 2x² + 4x - 8) - (5x³ + 12x² - 3x - 4)
<u>Step 2: Simplify</u>
- [Distributive Property] Distribute negative: 3x³ - 2x² + 4x - 8 - 5x³ - 12x² + 3x + 4
- Combine like terms (x³): -2x³ - 2x² + 4x - 8 - 12x² + 3x + 4
- Combine like terms (x²): -2x³ - 14x² + 4x - 8 + 3x + 4
- Combine like terms (x): -2x³ - 14x² + 7x - 8 + 4
- Combine like terms: -2x³ - 14x² + 7x - 4
The width used for the car spaces are taken as a multiples of the width of
the compact car spaces.
Correct response:
- The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>
Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.
We have;
Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)
New space design = 16·x + 9×(a·x) = x·(16 + 9·a)
When the dimensions of the initial and new arrangement are equal, we have;
10 + 12·a = 16 + 9·a
12·a - 9·a = 16 - 10 = 6
3·a = 6
a = 6 ÷ 3 = 2
a = 2
Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;
10 + 12·a < 16 + 9·a
Which gives;
x·(10 + 12·a) < x·(16 + 9·a)
Therefore;
The initial total car park space is less than the space required for 16
compact spaces and 9 full size spaces, therefore; the store owners are
incorrect.
Learn more about writing expressions here:
brainly.com/question/551090
