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tatyana61 [14]
3 years ago
15

A particle is moving along the curve y=22x+1−−−−−√y=22x+1. As the particle passes through the point (4,6)(4,6), its xx-coordinat

e increases at a rate of 44 units per second. Find the rate of change of the distance from the particle to the origin at this instant?

Mathematics
1 answer:
Ahat [919]3 years ago
3 0

Answer:

the rate of change of the distance from the particle to the origin at this instant = 3.33unit/secs

Step-by-step explanation:

The approach to solve the question involves , concept of rate of change in differentiation, implicit differentiation and appropriate substitution were made to get the rate of change of distance.

The steps are as shown in the attached file.

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The correct answer should be
B) having outliers
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2.<br> what do i put im confused and dont know how to do this
Paha777 [63]

Answer:

Step-by-step explanation:

The two dots on the bottom of this figure define the base of a triangle.  If we now use a compass to draw the blue arcs on either side, as shown, the arcs will intersect at two points.  A straight line drawn through these two points will be perpendicular to the base. The triangle will be isosceles and could be (but doesn't have to be) equilateral.

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3 years ago
Circle assignment! THANKS so much its worth so much of my grade
kogti [31]

Answer:

1. B) Figure B.

2. C) Figure C.

3. D) Figure D.

4. C) Figure C.

Step-by-step explanation:

Given: Radius of Circle A= 4

           Radius of Circle B= 5

           Radius of circle C= 6

           Radius of circle D= 7

Now, finding circumference and area of all the circle.

We know, circumference of circle= 2\pi r

Area of circle= \pi r^{2}

Where, r= radius of circle and π = 3.14

First, solving for figure A

Circumference= 2\times 3.14\times 4= 25.12\ cm

Area= 3.14\times 4^{2} = 50.24\ cm^{2}

Solving for Figure B

Circumference= 2\times 3.14\times 6= 31.4\ cm

Area= 3.14\times 5^{2} = 78.5\ cm^{2}

Solving for Figure C

Circumference= 2\times 3.14\times 6= 37.68\ cm

Area= 3.14\times 6^{2} = 113.04\ cm^{2}

Solving for Figure D

Circumference= 2\times 3.14\times 7= 43.96\ cm

Area= 3.14\times 7^{2} = 153.86\ cm^{2}

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6 0
3 years ago
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The percent of decrease in the amount of strawberries used annually is 15.9%

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