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tatyana61 [14]
2 years ago
15

A particle is moving along the curve y=22x+1−−−−−√y=22x+1. As the particle passes through the point (4,6)(4,6), its xx-coordinat

e increases at a rate of 44 units per second. Find the rate of change of the distance from the particle to the origin at this instant?

Mathematics
1 answer:
Ahat [919]2 years ago
3 0

Answer:

the rate of change of the distance from the particle to the origin at this instant = 3.33unit/secs

Step-by-step explanation:

The approach to solve the question involves , concept of rate of change in differentiation, implicit differentiation and appropriate substitution were made to get the rate of change of distance.

The steps are as shown in the attached file.

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Answer:

C. (1, -3)

Step-by-step explanation:

Plug in the x to get the y in the equation. The point must fit the formula.

Plug in C. (1, -3), in which x = 1, y = -3:

(-3) = 2(1) - 5

Simplify:

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C is your answer.

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If f(x) = -5-4 and g(x) = -3 -2 find (f-g)(x)
asambeis [7]

<u>Answer:</u>

The correct answer option is D. -5^x+3x-2

<u>Step-by-step-explanation:</u>

We are given the following two functions:

f(x)=-5^x-4

and

g(x)= -3x-2

We are to find (f-g)(x) so we will subtract the function g from function f, arrange the like terms together and combine them like shown below to get:

(f-g)(x) =(-5^x-4)-(-3x-2)

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Let the amount of time, in minutes, be x.

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500 - 6x [since it has 500 and is being drained with 6 per minute]

To find, we equate them and solve for x:

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