Answer:
8sin(x)cos³(x)
Step-by-step explanation:
sin(4x) +2 sin(2x) = 2sin(2x)*cos(2x) + 2sin(2x) = 2sin(2x)(cos2x + 1)=
= 2sin(2x)(cos²x - sin²x + cos²x + sin²x)=²2sin(2x)*(2cos²x)=
= 4*2sin(x)*cos(x)*cos²(x)= 8sin(x)cos³(x)
Answer:
b = 
Step-by-step explanation:
Given
k =
← multiply both sides by (v - b)
k(v - b) = brt ← distribute left side
kv - kb = brt ( subtract brt from both sides )
kv - kb - brt = 0 ( subtract kv from both sides )
- kb - brt = - kv ( multiply through by - 1 to clear the negatives )
kb + brt = kv ← factor out b from each term on the left
b(k + rt ) = kv ← divide both sides by (k + rt )
b = 
The answer is C: (-1, -8)