Given:
The system of equations is
...(i)
...(ii)
To find:
The number that must be multiplied with the second equation to eliminate the y-variable.
Solution:
Coefficient of y variable in equation (i) is 3 and in equation (ii) is -1.
To eliminate y-variable the absolute value of coefficients of y-variables should be same.
So, we need to multiply the second equation by 3 to eliminate the y-variable
Multiplying equation (ii) by 3, we get
...(iii)
Adding (i) and (iii), we get


Divide both sides by 7.

Put x=12 in (i).



Divide both sides by 10.

Therefore, x=12 and y=10.
Answer:
yes you are absolutely right
it will be the answer
If x=-1 => y-2=5=> y=7,x=-1
If x=0=> y+0=5=> y=5,x=0
If x=3=> y+6=5=> y=-1,x=3
2 because 8 divided by 4 is 2.
Answer:
The jug will hold 4,800 milliliters.
Step-by-step explanation:
Each liter is 1000 milliliters, and 4.8 • 100 = 4,800