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mr_godi [17]
3 years ago
14

PLEASE HELP!!!!! What is the value of x in the matrix equation below?

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right]  =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Matrix equality gives,

1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2

Solving the equations together,

y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10

We can see that the equations are not consistent.

There is no solution.

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Answer:

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Step-by-step explanation:

Given the expression, x² - x - 12, let's factorise to find the value of p and q using the table, for which we would have the expression simplified as (x + p)(x + q)

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Thus, from the table given, the row containing the values of p(3) and q(-4) gives us = -1 (p+q) . p = 3, q = -4 would be our values to use to factor x² - x - 12, as multiplying both will also give us "-12".

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