Answer:
The area of the trapezium is 
Step-by-step explanation:
Area of a trapezium:
This formula is valid if b1 and b2 are parallel and h is perpendicular to both.
Since the trapezium given in the problem satisfies those conditions, we use the formula with:
b1=15 cm
b2=7 cm
h=6.8 cm
The area of the trapezium is
i only see numbers not no square
Answer:
{- 2, - 4, - 6, - 8, - 10 }
Step-by-step explanation:
Given
f(x) = 2x - 6 with domain { - 2, - 1, 0, 1, 2 }
To obtain the range substitute the values of x from the domain into f(x)
f(- 2) = 2(- 2) - 6 = - 4 - 6 = - 10
f(- 1) = 2(- 1) - 6 = - 2 - 6 = - 8
f(0) = 2(0) - 6 = 0 - 6 = - 6
f(1) = 2(1) - 6 = 2 - 6 = - 4
f(2) = 2(2) - 6 = 4 - 6 = - 2
Range is { - 2, - 4, - 6, - 8, - 10 }
(-3, 3) because it is the intersection point.
This can solved graphically, using algebraic manipulation or differential calculus.
Plotting the equation will generate a parabola. The vertex represents the point where the ball will reach the maximum height.
The vertex can be determined by completing the square
h = -16t2 + 45t + 5
h - 5 = -16(t2 - 45/16t)
h - 5 - 2025/64 = -16(t2 - 45/16t + 2025/1024)
(-1/16)(h - 2345/64) = (t - 45/32)^2
The vertex is
(45/32,2345/64) or (1.41,36.64)
The maximum height is 36.64 ft
Using calculus, taking the first derivative of the equation and equating to 0
dh/dt = 0 = -32t + 45
t = 45/32
Substituting this value to the equation
h = -16(45/32)^2 + 45(45/32) + 5
h = 36.64 ft
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