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3 years ago

What is the measure of angle R ? hey guys 50 points! plz help in middle of my final

Mathematics

1 answer:

larisa [96]3 years ago

7 0

Answer:

29 degrees I think

Step-by-step explanation:

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igomit [66]

X=3
LOM and KOL are equivalent, so the equation is 43=6x+25 :)

5 0

3 years ago

Choose the letter of the number with your greatest absolute value?

Zolol [24]

The answer is of course E -340

6 0

3 years ago

Which of the following equations is equivalent to S=pi r^2 h

lara31 [8.8K]

The equation that is equivalent to S=pi r^2 h is h = S/pir^2

<h3>Subject of formula</h3>

This is a way of representing a variable with another. Given the equation

S=pi r^2 h

We are to make 'h" the subject of the formula.

Divide both sides by pir^2

S/pir^2 =pi r^2 h/pir^2

h = S/pir^2

Hence the equation that is equivalent to S=pi r^2 h is h = S/pir^2

Learn more on subject of formula here: brainly.com/question/657646

#SPJ1

4 0

2 years ago

The perimeter of an isosceles triangle less than 20 inches. If the base is 5 inches, what is the maximum length of each of the l

ser-zykov [4K]

Answer:

7.5 inches

Step-by-step explanation:

take the 5 away from the 20, you have 15 inches left. Isosceles triangles have two equal sides; 15 divided into two equally is 7.5

4 0

3 years ago

Evaluate the six trigonometric functions of the angle 0.

Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

$\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2$

$18^2 =10^2+\text{opposite}^2$

$324=100+\text{opposite}^2$

Subtract 100 from both sides.

$224=\text{opposite}^2$

Taking square root on both sides.

$4\sqrt{14}=\text{opposite}$

Using trigonometric ratio formula:

$$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}$

$$\sin\theta =\frac{4\sqrt{14} }{18}$

$$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}$

$$\csc\theta =\frac{18}{4\sqrt{14} }$

$$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}$

$$\cos \theta=\frac{10}{18}$

$$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}$

$$\sec \theta=\frac{18 }{10}$

$$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}$

$$\tan \theta=\frac{4\sqrt{14} }{10}$

$$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}$

$$\cot \theta=\frac{10}{4\sqrt{14} }$

8 0

3 years ago