Answer:
Using the formula:

where
A is the total amount
P is the principal
I is the Simple Interest
As per the statement:
Principal(P) = 5300 rupees.
rate of interest(r) = 6.5% = 0.065
Total amount(A) = 6678 rupees.
Then using above formula we have;

Subtract 5300 both sides we get;

or

We have to find the time period.
Using formula of Simple interest:

where r is the rate of interest (in decimal)
here, r = 6.5% = 0.065
Substitute the given values top find t:

⇒
Divide both sides by 344.5 we have;

Therefore, the time period t in years is 4 years
Answer: 5y + 4x = - 10
Step-by-step explanation:
Two lines are said to be perpendicular if the product of their gradients = -1.
If the gradient of the first line is
and the gradient of the second line is
, if the lines are perpendicular, them
x
= -1 , that is
= 
The equation of the line given is 5x - 4y = -3 , we need to write this equation in slope - intercept form in order to find the slope.
The equation in slope -intercept form is given as :
y =mx + c , where m is the slope and c is the y - intercept.
Writing the equation in this form , we have
5x - 4y = + 3
4y = 5x -+3
y = 5x/4 + 3/4
comparing with the equation y = mx + c , then
= 5/4
Which means that
= -4/5 and the line passes through the point ( -5 , 2 ).
Using the equation of line in slope - point form to find the equation of the line;
y -
= m ( x -
)
y - 2 = -4/5 ( x +5)
5(y - 2 ) = -4 ( x + 5 )
5y - 10 = -4x - 20
5y + 4x = - 10
1) We are given points on the line of the graph (0,3) and (1,1).
Rise/run represents the slope of the line.
Rise/run = -2/1 = -2.
Therefore, slope of the line is -2.
<h3>Correct option is A) -2 .</h3>
2) Given equation y=7.5x-5.
From the graph we can see that line crosses x-axis at 0.667.
But we don't find any such option.
But we can see line crossing y-axis is -5.
It seems that we need to find the point where line cut y-axis.
<h3>Therefore, correct option is C option.</h3><h3>C) - 5</h3>
Yes your correct but thats not a question