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2 years ago

PLEASE HELLLLLLLLLLLLLLP!

Mathematics

2 answers:

Vlad [161]2 years ago

5 0

Answer:

What do you need ?.....

Vinvika [58]2 years ago

5 0

You should add photograph or smth for answers :/

You might be interested in

There is a 10% off sale on laptop computers. If someone saves $35 on a laptop, what was its original cost?

IceJOKER [234]

Answer:

The original cost is $350

Step-by-step explanation:

Let's assume

original cost of computer is x

There is a 10% off sale on laptop computers

So, amount saved is

$=\frac{10}{100}x=0.10x$

now, we are given

someone saves $35 on a laptop

so, we can set them equal

and then we can solve for x

$0.10x=35$

we can divide both sides by 0.10

and we get

$x=350$

So,

The original cost is $350

4 0

2 years ago

Marcus wants to buy a PS5 and some digital games. The console cost $725 and he plans to buy games that cost $45. He only has $98

wariber [46]

I don’t know your question sooo I’m just going to go based on what I know.

980 - 725 = 225
$225 is how much you have left to buy games

In the end you can only buy about 3 games with $40 left

7 0

3 years ago

Jerry was using matrices to solve the system of three equations. He has shown all his steps. Did he make a mistake if so in what

melomori [17]

There are several ways to solve a system of equation; one of these ways is the use of matrix.

<em>Jerry made a mistake at step 2</em>

From the attachment, the step 1 is represented as:

$\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }$

The equation in step 2 is given as:

$\mathbf{R_2 = 5R_1 - R_2}$

This means that:

We subtract the elements of row 2 from the elements of row 1, multiplied by 5

So, we have:

$\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }$

Expand

$\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }$

Subtract corresponding cells

$\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }$

So, the new row 2 elements should be:

$\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }$

However, the row 2 elements of Jerry's steps are:

$\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }$

This means that:

Jerry made a mistake; and the mistake is at step 2