All categories

2 years ago

Translate the following verbal statement into an algebraic expression. Use x for your variable.

Mathematics

1 answer:

mafiozo [28]2 years ago

5 0

Answer:

x²/11 + 8

Step-by-step explanation:

We can decipher this algebraic expression going step by step.

1) "Eight more", meaning +8 (we can add this on later).

2) The "quotient of a number (x) squared and eleven", a quotient by definition means the answer to a quantity divided by another. The quantity in this case being x² divided by 11 (so, x²/11).

3) We can combine both of these, getting x²/11 + 8.

Your expression is x²/11 + 8.

- Similarly, you could reposition this equation like 8 + x²/11 (due to the communicative property of addition). Both answers would be acceptable.

You might be interested in

The value of a boat is $23,400. It loses 8% of its value every year. Find the approximate monthly percent decrease in value. Rou

Oduvanchick [21]

23400 x 8/100 = 1872 = the loss
1872 : 12 = 156= the loss each month
156/1872*100% = 8,33 % then round it

8 0

2 years ago

Please help if right I will give BRAINLIEST and 25 points

Allushta [10]

The total area is 448 in^2. Each triangle is 56 in^2 and each parallelogram is 140 in^2

5 0

2 years ago

Match the circle equations in general form with their corresponding equations in standard form. Not all will be used.

Xelga [282]

The standard form of the equation of a circumference is given by the following expression:

 $(x-h)^{2}+(y-k)^{2}=r^{2} \\ \\ where \ (h, k) \ is \ the \ center \ of \ the \ circumference \ and \ r \ the \ radius$

On the other hand, the general form is given as follows:

 $x^{2}+y^{2}+Dx+Ey+F=0 \\ \\ where: \\ D=-2h, \ E=-2k, \ F=h^{2}+k^{2}-r^{2}$ 

In this way, we can order the mentioned equations as follows:

Equations in Standard Form:

 $\bold{a)} \ (x-6)^{2}+(y-4)^{2}=56 \\ \bold{b)} \ (x-2)^{2} + (y+6)^{2}=60 \\ \bold{c)} \ (x+2)^{2}+(y+3)^{2}=18 \\ \bold{d)} \ (x+1)^{2}+(y-6)^{2}=46$

Equations in General Form:

$\bold{1)} \ x^{2}+y^{2}-4x+12y-20=0 \\ \bold{2)} \ x^{2}+y^{2}+6x-8y-10=0 \\ \bold{3)} \ 3x^{2}+3y^{2}+12x+18y-15=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 3, \ the \ equation \ becomes: \\ x^{2}+y^{2}+4x+6y-5=0 \\ \\ \bold{4)} \ 5x^{2}+5y^{2}-10x+20y-30=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 5, \ the \ equation \ becomes: \\ x^{2}+y^{2}-2x+4y-6=0 \\ \\ \bold{5)} \ 2x^{2}+2y^{2}-24x-16y-8=0 \\ \\ If \ we \ divide \ this \ equation \ by \ 2, \ the \ equation \ becomes: \\ x^{2}+y^{2}-12x-8y-4=0$

$\bold{6)} \ x^{2}+y^{2}+2x-12y$

So let's match each equation:

$\bold{From \ a)} \\ \\ (h,k)=(6,4),\ r=2\sqrt{14} \\ D=-12, \ E=-8 \\ F=-4$

Then, its general form is:

$x^{2}+y^{2}-12x-8y-4=0$

First. a) matches 5) 

$\bold{From \ b)} \\ \\ (h,k)=(2,-6),\ r=2\sqrt{15} \\ D=-4, \ E=12 \\ F=-20$

Then, its general form is:

$x^{2}+y^{2}-4x+12y-20=0$

Second. b) matches 1) 

$\bold{From \ c)} \\ \\ (h,k)=(-2,-3),\ r=3\sqrt{2} \\ D=4, \ E=6 \\ F=-5$

Then, its general form is:

$x^{2}+y^{2}+4x+6y-5=0$

Third. c) matches 3)

$\bold{From \ d)} \\ \\ (h,k)=(-1,6),\ r=\sqrt{46} \\ D=2, \ E=-12, \ F=-9$

Then, its general form is: $x^{2}+y^{2}+2x-12y-9=0$

Fourth. d) matches 6)

6 0

3 years ago

Read 2 more answers

Help me with this please

m_a_m_a [10]

36 is the value
answer

4 0

2 years ago

.........................................................................................................

gogolik [260]

Answer:

.................................................................................

........................

Step-by-step explanation:

Please MARK AS BRAINLIEST

4 0

3 years ago