(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
Answer:
IS 60 DEGRES
Step-by-step explanation:
U TIMES THE ANGLE
Q^2 - 125 = 0
q^2 = 125
q = +/- sqrt 125 = 11.18, -11.18
3y = -9x + 12
y = -3x + 4
Is this what you are looking for?
The answer is 10
The equation would look like
5(4)-4(3)+2
And if you solve it, you’ll get 10 as your answer
