PLEASE HELP!!! WHICH OF THE FOLLOWING FUNCTIONS IS GRAPHED BELOW?

Mathematics

1 answer:

SashulF [63]3 years ago

7 0

Answer: D.

Step-by-step explanation:

For an absolute value function, the vertex of $f(x) = |x+h| + k$ is defined as the point (-h, k) for the coordinate (x, y).

When x is equal to negative h, the value for x and value for h effectively cancel out, and only the positive k remains, hence the vertex being (-h, k).

The function given has a vertex at (2, 3). We know that the vertex of an absolute function is (-h, k), so h must equal -2 and k must equal 3.

The equation:

$f(x) = |x-2| + 3$

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Is 30/12 and 40/16 equivalent?

Flura [38]

30/12 in simplest form is 5/2 (cause 6 * 5 = 30 and 6 * 2 = 12)
40/16 in simplest form is 5/2 (cause 8 * 2 = 16 and 8 * 5 =40)
so yes they're equivalent;
30/12 = 40/16
Hope that helps :D have a nice day!

5 0

3 years ago

Read 2 more answers

Solve the system of linear equations for x and y.(cos θ)x + (sin θ)y=1(−sin θ)x + (cos θ)y = 0x=y=

lys-0071 [83]

Answer:

$\bold{x =cos\theta}\\\bold{y=sin\theta}$

Step-by-step explanation:

The given system of linear equations is:

$(cos\theta)x+(sin\theta)y=1\\(-sin\theta)x+(cos\theta)y=0$

We have to solve the equations for the values of $x, y$ .

Let us use elimination method in which we eliminate one of the variables from the two variables.

For this, let us multiply the first equation by $sin\theta$ and second equation by $cos\theta$

Now, the equations become:

$(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)$