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stepan [7]
3 years ago
8

Simplify the expression -3.3 + (-2.7). On the test, when Maureen simplified the expression she got 0.6. What mistake did Maureen

likely make when she simplified the expression?
Mathematics
2 answers:
Tju [1.3M]3 years ago
6 0

Answer:

-6

Step-by-step explanation:

She added a negative number with a positive number

Anton [14]3 years ago
3 0

Answer:

-6

Step-by-step explanation:

-3.3+(-2.7)= -3.3-2.7 = -6

Maureen probably did 3.3-2.7 instead of -3.3-2.7.

Hope this helps!!!

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mario62 [17]

<em>Good luck, you'll need it :)</em>

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Please can someone answer this question! Worth 15 points
Westkost [7]
The statements that aer true or not or whatever

hmm, let's try te sencnarios
remember the commutative property of multiplication
ab=ba
so

what if they are both negative?
well, the negatives would cancel to leave with positive
the oposite would be both positive resulting in a positive

if they are differnt signs then result is negative
oposite would be still different signs so still negative
true statment
8 0
3 years ago
Find |−5|.<br> A. −5<br> B. 5<br> C. one-fifth<br> D. –one-fifth<br><br> HELP!!!
Volgvan

recall that when it comes to absolute value expressions, once we remove the bars, it turns always to positive, so | -5 |, the bars go poof, and tada!!   5.

4 0
3 years ago
The sum of four consecutive even integers is -100. Find the absolute value of the smallest integer.
Talja [164]

Answer:

|–28|=28

Step-by-step explanation:

the four consecutive even integers are –22, –24, –26, –28

the absolute of the smallest is |–28|=28

3 0
3 years ago
The probability that a call received by a certain switchboard will be a wrong number is 0.02. Use the Poisson distribution to ap
MAXImum [283]

Answer:

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

The probability that a call received by a certain switchboard will be a wrong number is 0.02.

150 calls. So:

\mu = 150*0.02 = 3

Use the Poisson distribution to approximate the probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

Either there are less than two calls from wrong numbers, or there are at least two calls from wrong numbers. The sum of the probabilities of these events is 1. So

P(X < 2) + P(X \geq 2) = 1

We want to find P(X \geq 2). So

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-3}*3^{0}}{(0)!} = 0.0498

P(X = 1) = \frac{e^{-3}*3^{1}}{(1)!} = 0.1494

P(X < 2) = P(X = 0) + P(X = 1) = 0.0498 + 0.1494 = 0.1992

Then

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.1992 = 0.2008

0.2008 = 20.08% probability that among 150 calls received by the switchboard, there are at least two wrong numbers.

6 0
3 years ago
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