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3 years ago

Which set of side lengths cannot form a triangle? (screen shot attached)

Mathematics

1 answer:

antoniya [11.8K]3 years ago

6 0

Answer:

7in, 7in, and 15 in

Step-by-step explanation:

Based on the Triangle Inequality Theorem that states that the sum of any 2 sides of a triangle must be greater than the measure of the third side, we can find what set of lengths cannot form a triangle.

The only set that does not follow the theorem is the set with lengths 7in, 7in, and 15in. It does not follow the theorem because...

7 + 7 < 15 (which should not be true based on the theorem)

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Write an equation that describes the functions Functions: 0,0 1,4 2,8 3,12 Y=?

beks73 [17]

Answer:

y=4x

Step-by-step explanation:

Plug the numbers in:

4*0=0--> (0,0)

4*1=4-->(1,4)

4*2=8-->(2,8)

4*3=12-->(3,12)

4 0

3 years ago

How do I solve 1/10x+5=-3x-13+4x ?

Temka [501]

Answer:

x = 20

I am not sure if you wanted the answer. Sorry!

Step-by-step explanation:

Let's solve your equation step-by-step.

1/10 x + 5 = - 3x - 13 + 4x

Step 1: Simplify both sides of the equation.

1/10 x + 5 = - 3x - 13 + 4x

1/10 x + 5 = - 3x + - 13 + 4x

1/10 x + 5 = (- 3x + 4x) + (- 13)

1/10 x + 5 = x + - 13

1/10 x + 5 = x - 13

Step 2: Subtract x from both sides.

1/10 x + 5 - x = x - 13 - x

- 9/10 x + 5 = - 13

Step 3: Subtract 5 from both sides

- 9/10 x + 5 - 5 = - 13 - 5

- 9/10 x = - 18

Step 4: Multiply both sides by 10/(- 9).

(10/ - 9) * (- 9/10 x) = (01/ - 9) * (- 18)

x = 20

Hope this helps!

4 0

3 years ago

Read 2 more answers

What is this bruh i need help?

dolphi86 [110]

Answer:

what do you need answers for

Step-by-step explanation:

5 0

3 years ago

The square of X varies inversely as the square root of Y and directly as the variable M. When M = 27 and Y = 16, then X = 9. Fin

irakobra [83]

Answer:

$Y = 441$

Step-by-step explanation:

Given

M = 27 when Y = 16 and X = 9

Required

Find Y when M = 7 and X = 2

We start by getting the algebraic representation of the given statement

$X^2 \alpha \frac{1}{\sqrt Y} \alpha M$

Convert the variation to an equation; we have

$X^2 = \frac{KM}{\sqrt Y}$

Where K is the constant of variation;

When M = 27; Y = 16; X = 9, the expression becomes

$9^2 = \frac{K * 27}{\sqrt{16}}$

This gives

$81 = \frac{k * 27}{4}$

Make K the subject of formula

$K = \frac{81* 4}{27}$

$K = \frac{324}{27}$

$K = 12$

Solving for Y when M = 7 and X = 2

Recall that $X^2 = \frac{KM}{\sqrt Y}$

Substitute values for K, M and X

$2^2 = \frac{12 * 7}{\sqrt{Y}}$

$4 = \frac{84}{\sqrt{Y}}$

Take square of both sides

$4^2 = (\frac{84}{\sqrt{Y}})^2$

$16 = \frac{7056}{Y}$

Make Y the subject of formula

$Y = \frac{7056}{16}$

$Y = 441$

3 0

3 years ago

Find the volume of a right cone if the radius of the base is 4ft and the height is 10ft.

Alisiya [41]

Volume of cone= pi×r^2×h/3
=167.55

4 0

4 years ago

Read 2 more answers