Answer: Our required probability is 0.11.
Step-by-step explanation:
Since we have given that
Number of workers in first shift = 21
Number of workers in second shift = 15
Number of workers in third shift = 13
We need to find the probability of choosing exactly two second shift workers and two third shift workers.
So, it becomes,
Hence, our required probability is 0.11.
Answer:
For this case the reliability of the sytem would be given by:
R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6
And replacing we got:
Step-by-step explanation:
We can assume that the system work in series
If we have in general n units the reliability of the system is the probability that unit 1 succeeds and unit 2 succeeds and all of the other units in the system succeed. fror n units must succeed for the system to succeed. The reliability of the system is then given by:
For this case the reliability of the sytem would be given by:
R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6
And replacing we got:
V that is potential diff is equal to current multiplied by resistance. This snows that v is proportional to current directly
278 would be it I think but not sure
Answer:
Step-by-step explanation:
Hello!
Multiply by distributing:
- Distribute 4 + √6
- Multiply
- Simplify
- Simplify
The final answer is 46 + 14√6