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3 years ago

If your computer has a ________, someone else can gain access to it undetected.

1 answer:

3 0

If your computer has a rootkit, someone else can gain access to it undetected.
The term rootkit denotes a set of software tools typically malicious.
The purpose of this software is to enable access to a computer or areas of its software that is not otherwise allowed.
It is one of the most difficult types of malware to find and remove.

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I keep getting this error: postfix.cpp: In function ‘double RPN_evaluation(std::string)’: postfix.cpp:42:26: error: cannot conve

Svetradugi [14.3K]

Answer:

expr.at(g) returns a string, not a char. They are not the same thing and that is what the compiler is complaining about.

3 0

3 years ago

Set numMatches to the number of elements in userValues (having NUM_VALS elements) that equal matchValue. Ex: If matchValue = 2 a

xenn [34]

Answer:

import java.util.Scanner;

public class FindMatchValue {

public static void main (String [] args) {

final int NUM_VALS = 4;

int[] userValues = new int[NUM_VALS];

int i = 0;

int matchValue = 0;

int numMatches = -99; // Assign numMatches with 0 before your for loop

userValues[0] = 2;

userValues[1] = 2;

userValues[2] = 1;

userValues[3] = 2;

matchValue = 2;

numMatches=0;

for(i=0;i<NUM_VALS;i++)

{

if(userValues[i]==matchValue)//cheking if the array element is equal to match value.

{

numMatches++;

}

System.out.println(numMatches);//printing the matchvalue.

}

Output:-

Explanation:

First I have set the value numMatches to 0 before the loop.Then I have user the for loop to iterate over the array.In the for loop I am checking that the array element is equal to the matchValue or not if it is equal then increasing the numMatches by 1.Then at last print the value of numMatches.

5 0

3 years ago

PlZZZZZZZ help will give Brainliest

dalvyx [7]

Answer:

Phone

Explanation:

3 0

2 years ago

Read 2 more answers

If userA wants to send a secure message to userB using an asymmetric cryptographic algorithm, which key does userB use to decryp

ANTONII [103]

Answer:

userB will use his/her private key.

Explanation:

The steps involved in using asymmetric cryptographic algorithm are as follow:

1. Each user generates a pair of keys to be used for the encryption and decryption of messages.

2. Each user places one of the two keys in a public register or other accessible file. This is the public key. The companion key is kept private.

3. If UserA wishes to send a confidential message to UserB, UserA encrypts the message using UserB's public key.

4. When UserB receives the message, she decrypts it using her private key.

4 0

3 years ago

Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria

butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

if side1 == side2 == side3:

print("Equilateral Triangle")

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

else:

print("Scalene Triangle")

else:

print("Invalid Triangle")

else:

print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

if side1 == side2 == side3:

print("Equilateral Triangle")

Check if the triangle is isosceles

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

Otherwise, it is scalene

else:

print("Scalene Triangle")

Print invalid, if the sides do not make a valid triangle

else:

print("Invalid Triangle")

Print invalid, if the any of the sides are negative

else:

print("Invalid Triangle")

4 0

3 years ago